Bash 日期/时间算法
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Bash date/time arithmetic
提问by Deniz Dogan
I have a little Bash script which suspends the computer after a given number of minutes. However, I'd like to extend it to tell me what the time will be when it will be suspended, so I can get a rough idea of how long time I have left so to speak.
我有一个小 Bash 脚本，它在给定的分钟数后挂起计算机。但是，我想延长它以告诉我暂停的时间是什么时候，这样我就可以大致了解我还剩下多长时间可以这么说。
#!/bin/sh
let SECS=*60
echo "Sleeping for" "minutes, which is" $SECS "seconds."
sleep $SECS &&
pm-suspend
The only argument to the script will be how many minutes from now the computer should be suspended. All I want to add to this script is basically an echosaying e.g. "Sleeping until HH:nn:ss!". Any ideas?
脚本的唯一参数是从现在起计算机应该挂起的分钟数。我想添加到这个脚本的基本上是一个echo说法，例如“Sleeping until HH:nn:ss!”。有任何想法吗？
回答by Deniz Dogan
Found out how.
发现如何。
echo "The computer will be suspended at" $(date --date "now minutes")
回答by Michiel Buddingh
On BSD-derived systems, you'd use
在 BSD 派生的系统上，你会使用
date -r $(( $(date "+%s") + * 60 ))
i.e. get the current date in seconds, add the number of minutes, and feed it back to date.
Yeah, it's slightly less elegant.
即以秒为单位获取当前日期，添加分钟数，并将其反馈到日期。
是的，它稍微不那么优雅。
回答by Chris
on linux
在 linux 上
SECS=`date "+$s"`
SECS=$(( SECS + * 60 ))
date --date $SECS
