Jquery:悬停时显示/隐藏 div。点击显示
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Jquery: show/hide div on hover. Show on click
提问by NvdB31
Let's assume I have a div with a .descriptionclass.
让我们假设我有一个带有.description类的 div 。
I would like div.descriptionto be shown when user hovers over another div, with the .imageclass.
div.description当用户将鼠标悬停在另一个 div 上时,我希望显示.image该类。
However, when user clicks on div.image, I would like div.descriptionto stay visible. So if user clicks on .image, the mouseleaveevent should not be applied.
但是,当用户点击 时div.image,我希望div.description保持可见。因此,如果用户单击.image,则mouseleave不应应用该事件。
Lastly, when user clicks on the .imageagain, the hover function should be activated again. So that when mouse leaves .image1, div.descriptionwill be hidden again.
最后,当用户.image再次单击时,应再次激活悬停功能。这样当鼠标离开时.image1,div.description将再次隐藏。
Hope you guys can help me!
希望大家帮帮我!
回答by Pankaj Sharma
var cancel = false;
$(".another").hover(function(){
$("div.description").show();
},function(){
if(!cancel)
$("div.description").hide();
});
$(".image").click(function(){
cancel = (cancel)?false: true;
});
回答by Mihai Matei
You may try something like this: http://jqversion.com/#!/CCvqpwh
你可以试试这样的:http: //jqversion.com/#!/CCvqpwh
$('.image').bind('mouseenter', function(){
$('.description').show();
}).bind('mouseleave', function(){
$('.description').hide();
}).click(function(){
if (!$(this).hasClass('clicked')){
$(this).addClass('clicked');
$(this).unbind('mouseleave');
} else {
$(this).removeClass('clicked');
$(this).bind('mouseleave', function(){
$('.description').hide();
})
}
});
回答by Manish Negi
Use this script
使用这个脚本
jQuery(document).ready(function() {
jQuery('.overlay').hide();
});
jQuery(document).ready(function() {
jQuery('.element, .element-1').hover(function() {
jQuery('.overlay').show();
},
function() {
jQuery('.overlay').hide();
});
});
回答by underscore
You can bind two events to same elements like bellow.And use separate function to get what your want
您可以将两个事件绑定到相同的元素,例如 bellow.And 使用单独的函数来获得您想要的
var myFunction1 = function() {
$('div.description').show();
}
var myFunction2 = function() {
// do whatever you want
}
$('div.image')
.click(myFunction1)
.mouseover(myFunction2)

