Java Spring Boot REST @RequestParam 未被验证
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/38614903/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Spring Boot REST @RequestParam not being Validated
提问by ptimson
I have tried a number of examples from the net and cannot get Spring to validate my query string parameter. It doesn't seem execute the REGEX / fail.
我从网上尝试了许多示例,但无法让 Spring 验证我的查询字符串参数。似乎没有执行 REGEX / 失败。
package my.controller;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.bind.annotation.RestController;
import javax.validation.Valid;
import javax.validation.constraints.Pattern;
import static org.springframework.web.bind.annotation.RequestMethod.GET;
@RestController
public class MyController {
private static final String VALIDATION_REGEX = "^[0-9]+(,[0-9]+)*$";
@RequestMapping(value = "/my/{id}", method = GET)
public myResonseObject getMyParams(@PathVariable("id") String id,
@Valid @Pattern(regexp = VALIDATION_REGEX)
@RequestParam(value = "myparam", required = true) String myParam) {
// Do Stuff!
}
}
Current behaviour
当前行为
PASS - /my/1?myparam=1
PASS - /my/1?myparam=1,2,3
PASS - /my/1?myparam=
PASS - /my/1?myparam=1,bob
Desired behaviour
期望的行为
PASS - /my/1?myparam=1
PASS - /my/1?myparam=1,2,3
FAIL - /my/1?myparam=
FAIL - /my/1?myparam=1,bob
Thanks
谢谢
采纳答案by Jaiwo99
You need add @Validated to your class like this:
您需要像这样将 @Validated 添加到您的类中:
@RestController
@Validated
class Controller {
// ...
}
UPDATE:
更新:
you need to configure it properly.. add this bean to your context:
您需要正确配置它.. 将此 bean 添加到您的上下文中:
@Bean
public MethodValidationPostProcessor methodValidationPostProcessor() {
return new MethodValidationPostProcessor();
}
Example to handle exception:
处理异常的示例:
@ControllerAdvice
@Component
public class GlobalExceptionHandler {
@ExceptionHandler
@ResponseBody
@ResponseStatus(HttpStatus.BAD_REQUEST)
public Map handle(MethodArgumentNotValidException exception) {
return error(exception.getBindingResult().getFieldErrors()
.stream()
.map(FieldError::getDefaultMessage)
.collect(Collectors.toList()));
}
@ExceptionHandler
@ResponseBody
@ResponseStatus(HttpStatus.BAD_REQUEST)
public Map handle(ConstraintViolationException exception) {
return error(exception.getConstraintViolations()
.stream()
.map(ConstraintViolation::getMessage)
.collect(Collectors.toList()));
}
private Map error(Object message) {
return Collections.singletonMap("error", message);
}
}
回答by Achille_vanhoutte
You can try this
你可以试试这个
@Pattern(regexp="^[0-9]+(,[0-9]+)*$")
private static final String VALIDATION_REGEX;
(pay attention for the final modifier)or else
(注意最后的修饰符)否则
@Pattern()
private static final String VALIDATION_REGEX = "^[0-9]+(,[0-9]+)*$";
And then remove @Pattern(regexp = VALIDATION_REGEX)from your method and keep only the @Validannotation:
然后从您的方法中删除@Pattern(regexp = VALIDATION_REGEX)并仅保留@Valid注释:
public myResonseObject getMyParams(@PathVariable("id") String id, @Valid @RequestParam(value = "myparam", required = true) String myParam) {
回答by Gangnus
You have incorrect regex
你有不正确的正则表达式
"^[0-9]+(,[0-9]+)*$"
It will never parse
它永远不会解析
1,bob
Maybe, you need:
也许,你需要:
"^\w+(,\w+)*$"
And if you need to parse also an empty line, use:
如果您还需要解析一个空行,请使用:
"^(\w+(,\w+)*)?$"