node.js 类名 jade 中的变量
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variable in class name jade
提问by user1860758
I can't set a variable name in a class in jade:
我无法在 jade 的类中设置变量名:
.flag_#{ session.locale } #{ session.locale }
I have:
我有:
<div class="flag_" >en</div>
And I'd like to have
我想要
<div class="flag_en" >en</div>
Thanks
谢谢
回答by karaxuna
Try this (have not tested):
试试这个(没有测试过):
div(class="flag_#{ session.locale }") session.locale
回答by Pablo Armentano
As for [email protected] works this way:
至于 [email protected] 是这样工作的:
div(class="flag_" + session.locale) session.locale
回答by davidnknight
Here's another approach:
这是另一种方法:
mixin formButton(text, type, extra_classes)
- var default_classes = 'btn btn-primary'
if extra_classes
- var classes = default_classes + ' ' + extra_classes
else
- var classes = default_classes
if type
button(class=classes type=type) !{text}
else
button(class=classes type="submit") !{text}
Example 1:
示例 1:
Usage:
用法:
+formButton('Text')
Result:
结果:
<button type="text" class="btn btn-primary" type="submit">Text</button>
Example 2:
示例 2:
Usage:
用法:
+formButton('Text', 'button')
Result:
结果:
<button type="text" class="btn btn-primary" type="button">Text</button>
Example 3:
示例 3:
Usage:
用法:
+formButton('Text', 'button', 'extra-class')
Result:
结果:
<button type="text" class="btn btn-primary extra-class" type="button">Text</button>
回答by dotslashlu
You can also use conditional statementsto do this like
您还可以使用条件语句来执行此操作
if liked == true
span.like.active
else
span.like

