在 Python 循环中构建字典 - 列表和字典推导式

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时间:2020-08-19 12:54:50  来源:igfitidea点击:

Build Dictionary in Python Loop - List and Dictionary Comprehensions

pythonfor-loop

提问by Mike

I'm playing with some loops in python. I am quite familiar with using the "for" loop:

我在 python 中玩一些循环。我非常熟悉使用“for”循环:

for x in y:
    do something

You can also create a simple list using a loop:

您还可以使用循环创建一个简单的列表:

i = []
for x in y:
   i.append(x)

and then I recently discovered a nice efficient type of loop, here on Stack, to build a list (is there a name for this type of loop? I'd really like to know so I can search on it a little better):

然后我最近在 Stack 上发现了一种很好的高效循环类型来构建一个列表(这种类型的循环有名字吗?我真的很想知道这样我可以更好地搜索它):

[x.name for x in y]

Ok, that being said, I wanted to go further with the last type of loop and I tried to build a python dictionary using the same type of logic:

好吧,话虽如此,我想更进一步地使用最后一种类型的循环,并尝试使用相同类型的逻辑构建一个 python 字典:

{x[row.SITE_NAME] = row.LOOKUP_TABLE for row in cursor}

instead of using:

而不是使用:

x = {}
for row in cursor:
   x[row.SITE_NAME] = row.LOOKUP_TABLE

I get an error message on the equal sign telling me it's an invalid syntax. I believe in this case, it's basically telling me that equal sign is a conditional clause (==), not a declaration of a variable.

我在等号上收到一条错误消息,告诉我这是一个无效的语法。我相信在这种情况下,它基本上告诉我等号是条件子句(==),而不是变量的声明。

My second question is, can I build a python dictionary using this type of loop or am I way off base? If so, how would I structure it?

我的第二个问题是,我可以使用这种类型的循环构建一个 python 字典还是我离基地很远?如果是这样,我将如何构建它?

采纳答案by lejlot

The short form is as follows (called dict comprehension, as analogy to the list comprehension, set comprehensionetc.):

简短形式如下(称为dict comprehension,类似于list comprehensionset comprehension等):

x = { row.SITE_NAME : row.LOOKUP_TABLE for row in cursor }

so in general given some _containerwith some kind of elements and a function _valuewhich for a given element returns the value that you want to add to this key in the dictionary:

所以一般来说,给定一些_container具有某种元素的函数和一个函数_value,该函数对于给定元素返回您要添加到字典中此键的值:

{ _key : _value(_key) for _key in _container }

回答by Carsten

You can do it like this:

你可以这样做:

x = dict((row.SITE_NAME, row.LOOKUP_TABLE) for row in cursor)

回答by Wayne Werner

What you're using is called a list comprehension. They're pretty awesome ;)

您正在使用的称为列表理解。他们非常棒;)

They have a cousin called a generator expression that works like a list comprehension but instead of building the list all at once, they generate one item at a time. Hence the name generator. You can even build functions that are generators - there are plenty of questions and sites to cover that info, though.

他们有一个叫做生成器表达式的表亲,它的工作方式类似于列表推导式,但不是一次构建所有列表,而是一次生成一个项目。因此名称生成器。您甚至可以构建作为生成器的函数——不过,有很多问题和网站可以涵盖这些信息。

You can do one of two things:

您可以执行以下两项操作之一:

x = dict(((row.SITE_NAME, row.LOOKUP_TABLE) for row in cursor))

Or, if you have a sufficiently new version of Python, there is something called a dictionary comprehension - which works like a list comprehension, but produces a dictionary instead.

或者,如果你有一个足够新的 Python 版本,有一种叫做字典推导的东西——它的工作原理类似于列表推导,但生成的是一个字典。

x = {row.SITE_NAME : row.LOOKUP_TABLE for row in cursor}