xcode 如何复制 NSMutableArray
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How to copy a NSMutableArray
提问by Blane Townsend
I would simply like to know how to copy a NSMutableArray so that when I change the array, my reference to it doesn't change. How can I copy an array?
我只想知道如何复制 NSMutableArray 以便当我更改数组时，我对它的引用不会改变。如何复制数组？
回答by Regexident
There are multiple ways to do so:
有多种方法可以做到这一点：
NSArray *newArray = [NSMutableArray arrayWithArray:oldArray];
NSArray *newArray = [[[NSMutableArray alloc] initWithArray:oldArray] autorelease];
NSArray *newArray = [[oldArray mutableCopy] autorelease];
These will all create shallow copies, though.
不过，这些都会创建浅拷贝。
(Edit:If you're working with ARC, just delete the calls to autorelease.)
（编辑：如果您正在使用 ARC，只需删除对 的调用autorelease。）
For deep copiesuse this instead:
对于深拷贝，请改用它：
NSMutableArray *newArray = [[[NSMutableArray alloc] initWithArray:oldArray copyItems:YES] autorelease];
Worth noting:For obvious reasons the latter will require all your array's element objects to implement NSCopying.
值得注意的是：出于显而易见的原因，后者将需要您的所有数组元素对象来实现NSCopying.
