java MySQL语法错误异常

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时间:2020-10-31 15:50:36  来源:igfitidea点击:

MySQLSyntaxErrorException

javamysqljdbcphpmyadmin

提问by skynyrd

I've just started to learn MySQL and JDBC.

我刚刚开始学习 MySQL 和 JDBC。

I created a table called testdb using phpmyadmin. Table just has 2 columns called first and last. When I am trying to connect the database from my java class, I get MySQLSyntaxError. However I could not figure it out.

我使用 phpmyadmin 创建了一个名为 testdb 的表。表只有 2 列,分别称为 first 和 last。当我尝试从我的 java 类连接数据库时,出现 MySQLSyntaxError。但是我想不通。

Here is my class:

这是我的课:

import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;

public class Main {

    public static void main(String[] args) throws ClassNotFoundException, SQLException {
        String url = "jdbc:mysql://localhost:3306/testdb";

        //Accessing driver from the JAR file.
        Class.forName("com.mysql.jdbc.Driver");

        //Creating a variable for the connection "con"
        Connection con = DriverManager.getConnection(url,"root","password");

        //Here is the query
        PreparedStatement statement = con.prepareStatement("select * from name");

        //Execute query
        ResultSet result = statement.executeQuery();

        while(result.next()) {
            System.out.println(result.getString(1) + " " + result.getString(2));
        }


    }

}

And here is the exception:

这是例外:

Exception in thread "main" com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Table 'testdb.name' doesn't exist
    at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
    at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:57)
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:45)
    at java.lang.reflect.Constructor.newInstance(Constructor.java:525)
    at com.mysql.jdbc.Util.handleNewInstance(Util.java:411)
    at com.mysql.jdbc.Util.getInstance(Util.java:386)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1053)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4096)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4028)
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2490)
    at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2651)
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2734)
    at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2155)
    at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:2322)
    at Main.main(Main.java:22)

Thank you for your help

谢谢您的帮助

回答by kosa

MySQLSyntaxErrorException: Table 'testdb.name' doesn't exist

error is pretty much descriptive. There is not table with name "name" in testdbschema.

错误几乎是描述性的。testdb架构中没有名称为“name”的表。

I created a table called testdbusing phpmyadmin.

我使用 phpmyadmin创建了一个名为testdb的表。

If you have created table testdbthen it should be select * from testdb. isn't it?

如果您已经创建了表,testdb那么它应该是select * from testdb. 不是吗?

回答by KyelJmD

You've created a table named testdbtherefore your query should be

您已经创建了一个名为testdb的表,因此您的查询应该是

select * from testdb 

not select * from name

不是 select * from name

you should really check your stacktraces.

你真的应该检查你的堆栈跟踪。