C# 将字符串转换为日期时间
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Converting a String to DateTime
提问by
How do you convert a string such as 2009-05-08 14:40:52,531into a DateTime?
您如何将字符串转换2009-05-08 14:40:52,531为 a DateTime？
回答by gehsekky
try this
尝试这个
DateTime myDate = DateTime.Parse(dateString);
a better way would be this:
更好的方法是这样的：
DateTime myDate;
if (!DateTime.TryParse(dateString, out myDate))
{
// handle parse failure
}
回答by Sander
You have basically two options for this. DateTime.Parse()and DateTime.ParseExact().
为此，您基本上有两种选择。DateTime.Parse()和DateTime.ParseExact()。
The first is very forgiving in terms of syntax and will parse dates in many different formats. It is good for user input which may come in different formats.
第一个在语法方面非常宽容，可以解析许多不同格式的日期。它适用于可能采用不同格式的用户输入。
ParseExact will allow you to specify the exact format of your date string to use for parsing. It is good to use this if your string is always in the same format. This way, you can easily detect any deviations from the expected data.
ParseExact 将允许您指定用于解析的日期字符串的确切格式。如果您的字符串始终采用相同的格式，最好使用它。这样，您可以轻松检测与预期数据的任何偏差。
You can parse user input like this:
您可以像这样解析用户输入：
DateTime enteredDate = DateTime.Parse(enteredString);
If you have a specific format for the string, you should use the other method:
如果您有特定的字符串格式，则应使用其他方法：
DateTime loadedDate = DateTime.ParseExact(loadedString, "d", null);
"d"stands for the short date pattern (see MSDN for more info) and nullspecifies that the current culture should be used for parsing the string.
回答by CMS
Since you are handling 24-hour based time and you have a comma separating the seconds fraction, I recommend that you specify a custom format:
由于您正在处理基于 24 小时的时间并且您有一个逗号分隔秒部分，我建议您指定自定义格式：
DateTime myDate = DateTime.ParseExact("2009-05-08 14:40:52,531", "yyyy-MM-dd HH:mm:ss,fff",
System.Globalization.CultureInfo.InvariantCulture);
回答by Umair Baig
string input;
DateTime db;
Console.WriteLine("Enter Date in this Format(YYYY-MM-DD): ");
input = Console.ReadLine();
db = Convert.ToDateTime(input);
//////// this methods convert string value to datetime
///////// in order to print date
Console.WriteLine("{0}-{1}-{2}",db.Year,db.Month,db.Day);
回答by Krishna
Try the below, where strDate is your date in 'MM/dd/yyyy' format
尝试以下操作，其中 strDate 是您的“MM/dd/yyyy”格式的日期
var date = DateTime.Parse(strDate,new CultureInfo("en-US", true))
回答by dev.bv
You could also use DateTime.TryParseExact() as below if you are unsure of the input value.
如果您不确定输入值，您也可以使用 DateTime.TryParseExact() 如下。
DateTime outputDateTimeValue;
if (DateTime.TryParseExact("2009-05-08 14:40:52,531", "yyyy-MM-dd HH:mm:ss,fff", System.Globalization.CultureInfo.InvariantCulture, System.Globalization.DateTimeStyles.None, out outputDateTimeValue))
{
return outputDateTimeValue;
}
else
{
// Handle the fact that parse did not succeed
}
回答by guneysus
Nobody seems to implemented an extension method. With the help of @CMS's answer:
似乎没有人实现扩展方法。在@CMS 的回答的帮助下：
Working and improved full source example is here: Gist Link
工作和改进的完整源代码示例在这里：Gist Link
namespace ExtensionMethods {
using System;
using System.Globalization;
public static class DateTimeExtensions {
public static DateTime ToDateTime(this string s,
string format = "ddMMyyyy", string cultureString = "tr-TR") {
try {
var r = DateTime.ParseExact(
s: s,
format: format,
provider: CultureInfo.GetCultureInfo(cultureString));
return r;
} catch (FormatException) {
throw;
} catch (CultureNotFoundException) {
throw; // Given Culture is not supported culture
}
}
public static DateTime ToDateTime(this string s,
string format, CultureInfo culture) {
try {
var r = DateTime.ParseExact(s: s, format: format,
provider: culture);
return r;
} catch (FormatException) {
throw;
} catch (CultureNotFoundException) {
throw; // Given Culture is not supported culture
}
}
}
}
namespace SO {
using ExtensionMethods;
using System;
using System.Globalization;
class Program {
static void Main(string[] args) {
var mydate = "29021996";
var date = mydate.ToDateTime(format: "ddMMyyyy"); // {29.02.1996 00:00:00}
mydate = "2016 3";
date = mydate.ToDateTime("yyyy M"); // {01.03.2016 00:00:00}
mydate = "2016 12";
date = mydate.ToDateTime("yyyy d"); // {12.01.2016 00:00:00}
mydate = "2016/31/05 13:33";
date = mydate.ToDateTime("yyyy/d/M HH:mm"); // {31.05.2016 13:33:00}
mydate = "2016/31 Ocak";
date = mydate.ToDateTime("yyyy/d MMMM"); // {31.01.2016 00:00:00}
mydate = "2016/31 January";
date = mydate.ToDateTime("yyyy/d MMMM", cultureString: "en-US");
// {31.01.2016 00:00:00}
mydate = "11/?????/1437";
date = mydate.ToDateTime(
culture: CultureInfo.GetCultureInfo("ar-SA"),
format: "dd/MMMM/yyyy");
// Weird :) I supposed dd/yyyy/MMMM but that did not work !?$^&*
System.Diagnostics.Debug.Assert(
date.Equals(new DateTime(year: 2016, month: 5, day: 18)));
}
}
}
回答by Amir Twito
DateTime dateTime = DateTime.Parse(dateTimeStr);
回答by M.R.T2017
Put this code in a static class> public static class ClassName{ }
将此代码放在静态类中> public static class ClassName{ }
public static DateTime ToDateTime(this string datetime, char dateSpliter = '-', char timeSpliter = ':', char millisecondSpliter = ',')
{
try
{
datetime = datetime.Trim();
datetime = datetime.Replace(" ", " ");
string[] body = datetime.Split(' ');
string[] date = body[0].Split(dateSpliter);
int year = date[0].ToInt();
int month = date[1].ToInt();
int day = date[2].ToInt();
int hour = 0, minute = 0, second = 0, millisecond = 0;
if (body.Length == 2)
{
string[] tpart = body[1].Split(millisecondSpliter);
string[] time = tpart[0].Split(timeSpliter);
hour = time[0].ToInt();
minute = time[1].ToInt();
if (time.Length == 3) second = time[2].ToInt();
if (tpart.Length == 2) millisecond = tpart[1].ToInt();
}
return new DateTime(year, month, day, hour, minute, second, millisecond);
}
catch
{
return new DateTime();
}
}
In this way, you can use
这样，您可以使用
string datetime = "2009-05-08 14:40:52,531";
DateTime dt0 = datetime.TToDateTime();
DateTime dt1 = "2009-05-08 14:40:52,531".ToDateTime();
DateTime dt5 = "2009-05-08".ToDateTime();
DateTime dt2 = "2009/05/08 14:40:52".ToDateTime('/');
DateTime dt3 = "2009/05/08 14.40".ToDateTime('/', '.');
DateTime dt4 = "2009-05-08 14:40-531".ToDateTime('-', ':', '-');
