Bash 脚本意外操作符
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Bash scripting unexpected operator
提问by Sonique
I'm writing script for git hook and have trouble with ifstatement inside while.
我正在为 git hook 编写脚本并且if在while.
File:
文件：
#!/bin/sh
while read oldrev newref ref
do
branch=$(git rev-parse --symbolic --abbrev-ref $ref)
if [ "a" == "a" ]
then
echo "Condition work"
fi
echo "$branch"
done
Error:
错误：
hooks/post-receive: 6: [: a: unexpected operator
I'll try with variables, double quotes but ifdoesn't work. What kind of error is here?
我会尝试使用变量，双引号，但if不起作用。这里有什么样的错误？
Thanks
谢谢
回答by mata
if [ "a" == "a" ]should be if [ "a" = "a" ].
if [ "a" == "a" ]应该是if [ "a" = "a" ]。
bashaccepts ==instead of =, but your /bin/shprobably isn't bash.
bash接受==而不是=，但你/bin/sh可能不是bash。
So either change the ==to =, or your shebang to #!/bin/bash
因此，要么将==to更改为=，要么将您的 shebang更改为#!/bin/bash
