C++ “非标准语法；使用‘&’创建指向成员的指针”错误 vs2015
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"non-standard syntax; use '&' to create a pointer to member" error vs2015
提问by Tomer
I have this function:
我有这个功能：
std::string Room::getUsersAsString(std::vector<User*> usersList, User * excludeUser)
{
std::string usersNames = " ";
for (int i = 0; i < usersList.size(); i++) {
if (usersList[i]->getUsername() != excludeUser->getUsername) {
usersNames.append(usersList[i]->getUsername);
usersNames.append(" ");
}
}
return usersNames;
}
Whenever I try to run the program, I get the following error:
每当我尝试运行该程序时，都会出现以下错误：
non-standard syntax; use '&' to create a pointer to member
Cant find out how to fix it.
无法找出如何修复它。
回答by Julian Declercq
If you use
如果你使用
if (usersList[i]->getUsername() != excludeUser->getUsername)
instead of
代替
if (usersList[i]->getUsername() != excludeUser->getUsername())
your compiler will think you want to use a function pointer instead of the method itself, and if you would have wanted to use a function pointer, you would still have to get the address of it (using &).
您的编译器会认为您想使用函数指针而不是方法本身，如果您想使用函数指针，您仍然需要获取它的地址（使用 &）。
So make sure you don't forget your () after a function call!
因此，请确保在函数调用后不要忘记您的 ()！
回答by SurvivalMachine
You are missing the function call parentheses in these lines:
您在这些行中缺少函数调用括号：
if (usersList[i]->getUsername() != excludeUser->getUsername) {
and
和
usersNames.append(usersList[i]->getUsername);
Try changing them into this:
尝试将它们更改为：
if (usersList[i]->getUsername() != excludeUser->getUsername()) {
and
和
usersNames.append(usersList[i]->getUsername());
