xcode 比较两个 NSDate
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Compare Between 2 NSDate
提问by or azran
i Have 2 NSDateobject the first is set to one month ahead and the seconed is set for today.
i want to check if today is after (Bigger) then the month ahead object.
我有 2 个NSDate对象，第一个设置为提前一个月，第二个设置为今天。我想检查今天是否在（更大）之后是前一个月的对象。
How can i do it?
我该怎么做？
回答by winsmith
You can use NSDate's comparemethod. Example:
您可以使用NSDate 的compare方法。例子：
switch ([dateOne compare:dateTwo]) {
case NSOrderedAscending:
// dateOne is earlier in time than dateTwo
break;
case NSOrderedSame:
// The dates are the same
break;
case NSOrderedDescending:
// dateOne is later in time than dateTwo
break;
}
回答by AliSoftware
Read the Date and Time Programming Guidea lot of Date & Time concepts (and how Cocoa handle them) are explained here in details, it is really worth reading.
阅读日期和时间编程指南，这里详细解释了很多日期和时间概念（以及 Cocoa 如何处理它们），非常值得一读。
Also, in the NSDate class Reference, you can find a dedicated section"Comparing dates" for all the methods used to compare two dates. So you should use laterDate:or earlierDate:methods that totally answer your question. You can also use the timeIntervalSinceDate:method and check the sign of the returned time interval (see once again the documentation on this)
此外，在NSDate 类参考中，您可以找到一个专门的部分“比较日期”，用于比较两个日期的所有方法。所以你应该使用laterDate:或earlierDate:方法来完全回答你的问题。您还可以使用该timeIntervalSinceDate:方法并检查返回时间间隔的符号（再次参见有关此的文档）
In general, don't hesitate to read the documentationas everythingis already explained in there in detail as you can see given those links
一般来说，请不要犹豫阅读文档，因为所有内容都已在那里详细解释，您可以在这些链接中看到
回答by jbat100
NSDate* earlierDate = [aDate earlierDate:anotherDate];
Return ValueThe earlier of the receiver and anotherDate, determined using timeIntervalSinceDate:. If the receiver and anotherDate represent the same date, returns the receiver.
返回值接收者和 anotherDate 中较早者，使用 timeIntervalSinceDate: 确定。如果接收者和另一个日期表示相同的日期，则返回接收者。
回答by Ron
go to this link:
转到此链接：
other wise convert your date to double and compare it. all related function are in this link.
否则明智地将您的日期转换为双倍并进行比较。所有相关功能都在此链接中。
