java 如何使用java从两个列表中获取不常见元素的列表？
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How to get the list of uncommon element from two list using java?
提问by Arunprasad
I need to get the list of uncommon element while comparing two lists . ex:-
我需要在比较两个列表时获取不常见元素的列表。前任：-
List<String> readAllName = {"aaa","bbb","ccc","ddd"};
List<String> selectedName = {"bbb","ccc"};
here i want uncommon elements from readAllName list ("aaa","ccc","ddd") in another list. Without Using remove()and removeAll().
在这里，我想要另一个列表中 readAllName 列表（“aaa”、“ccc”、“ddd”）中的不常见元素。不使用 remove() 和 removeAll()。
回答by assylias
Assuming the expected output is aaa, ccc, eee, fff, xxx(all the not-common items), you can use List#removeAll, but you need to use it twice to get both the items in name but not in name2 AND the items in name2 and not in name:
假设预期的输出是aaa, ccc, eee, fff, xxx（所有不常见的项目），您可以使用List#removeAll，但您需要使用它两次才能同时获取 name 中但不在 name2 中的项目以及 name2 中而不是 name 中的项目：
List<String> list = new ArrayList<> (name);
list.removeAll(name2); //list contains items only in name
List<String> list2 = new ArrayList<> (name2);
list2.removeAll(name); //list2 contains items only in name2
list2.addAll(list); //list2 now contains all the not-common items
As per your edit, you can't use removeor removeAll- in that case you can simply run two loops:
根据您的编辑，您不能使用removeor removeAll- 在这种情况下，您可以简单地运行两个循环：
List<String> uncommon = new ArrayList<> ();
for (String s : name) {
if (!name2.contains(s)) uncommon.add(s);
}
for (String s : name2) {
if (!name.contains(s)) uncommon.add(s);
}
回答by RNJ
You can use the Guava libraries to do this. The Setsclass has a differencemethod
您可以使用 Guava 库来执行此操作。该集合类有一个区别方法
You would have to run it twice I think to get all the differences from both sides.
我认为你必须运行它两次才能获得双方的所有差异。
