php 将月份从名称转换为数字
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convert month from name to number
提问by aslum
Is there an easy way to change $month = "July";so that $nmonth = 7(07would be fine too).
I could do a case statement, but surely there is already a function to convert?
EDIT:
I wish I could accept multiple answers, cause two of you basically gave me what I needed by your powers combined.
有一个简单的方法来改变$month = "July";，这样$nmonth = 7（07就可以了太）。我可以做一个 case 语句，但肯定已经有一个函数可以转换？编辑：我希望我能接受多个答案，因为你们两个基本上通过你们的力量给了我我需要的东西。
$nmonth = date('m',strtotime($month));
That will give the numerical value for $month.
Thanks!
这将给出 的数值$month。谢谢！
回答by Matthew
Try this:
尝试这个：
<?php
$date = date_parse('July');
var_dump($date['month']);
?>
回答by Sarfraz
Yes,
是的，
$date = 'July 25 2010';
echo date('d/m/Y', strtotime($date));
The mformats the month to its numerical representation there.
将m月份格式化为其数字表示形式。
回答by vkGunasekaran
An interesting look here, the code given by kelly works well,
一个有趣的样子，kelly 给出的代码运行良好，
$nmonth = date("m", strtotime($month));
but for the month of february, it won't work as expected when the current day is 30 or 31 on leap year and 29,30,31 on non-leap year.It will return 3as month number. Ex:
但是对于二月，当闰年的当前日期为 30 或 31 以及非闰年的 29,30,31 时，它不会按预期工作。它将返回3作为月份数。前任：
$nmonth = date("m", strtotime("february"));
The solution is, add the year with the month like this:
解决方案是，将年份与月份相加，如下所示：
$nmonth = date("m", strtotime("february-2012"));
I got this from this commentin php manual.
我从php 手册中的这个评论中得到了这个。
回答by Vineesh Kalarickal
$string = "July";
echo $month_number = date("n",strtotime($string));
returns '7' [month number]
返回 '7' [月数]
Use date("m",strtotime($string));for the output "08"
使用date("m",strtotime($string));的输出“08”
For more formats reffer this..
http://php.net/manual/en/function.date.php
有关更多格式，请参阅此 ..
http://php.net/manual/en/function.date.php
回答by lokeshpahal
you can also use this one:
你也可以使用这个：
$month = $monthname = date("M", strtotime($month));
回答by Ranjith Siji
$monthname = date("F", strtotime($month));
Fmeans full month name
F表示完整的月份名称
回答by Kelly Copley
$nmonth = date("m", strtotime($month));
回答by Ben Guthrie
It may be easiest to create a fake date so you can use the date function.
创建假日期可能是最简单的方法，因此您可以使用 date 函数。
Excellent reference here: http://php.net/manual/en/function.date.php
这里的优秀参考：http: //php.net/manual/en/function.date.php
Example:
例子：
<?
$month = 7;
$tempDate = mktime(0, 0, 0, $month, 1, 1900);
echo date("m",$tempDate);
?>
回答by Nikos Tsirakis
<?php
$monthNum = 5;
$monthName = date("F", mktime(0, 0, 0, $monthNum, 10));
echo $monthName; //output: May
?>
回答by PHP Ferrari
Use
用
date("F", mktime(0, 0, 0, ($month)));
where, $month value will be 1 -> 12
