Java 使用 Spring RestTemplate 发布带有对象的参数
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Using Spring RestTemplate to POST params with objects
提问by Matt Crysler
I am trying to send a POST request using Spring's RestTemplate functionality but am having an issue sending an object. Here is the code I am using to send the request:
我正在尝试使用 Spring 的 RestTemplate 功能发送 POST 请求，但在发送对象时遇到问题。这是我用来发送请求的代码：
RestTemplate rt = new RestTemplate();
MultiValueMap<String,Object> parameters = new LinkedMultiValueMap<String,Object>();
parameters.add("username", usernameObj);
parameters.add("password", passwordObj);
MyReturnObj ret = rt.postForObject(endpoint, parameters, MyRequestObj.class);
I also have a logging interceptor so I can debug the input parameters and they are almostcorrect! Currently, the usernameObjand passwordObjparameters appear as such:
我还有一个日志拦截器，所以我可以调试输入参数，它们几乎是正确的！目前，usernameObj和passwordObj参数如下所示：
{"username":[{"testuser"}],"password":[{"testpassword"}]}
What I wantthem to look like is the following:
我希望它们看起来如下：
username={"testuser"},password={"testpassword"}
Assume that usernameObjand passwordObjare Java objects that have been marshalled into JSON.
假设usernameObj和passwordObj是已编组为 JSON 的 Java 对象。
What am I doing wrong?
我究竟做错了什么？
采纳答案by Matt Crysler
Alright, so I ended up figuring this out, for the most part. I ended up just writing a marshaller/unmarshaller so I could handle it at a much more fine grained level. Here was my solution:
好吧，所以我最终弄清楚了这一点，在很大程度上。我最终只写了一个编组器/解组器，所以我可以在更细粒度的级别处理它。这是我的解决方案：
RestTemplate rt = new RestTemplate();
// Create a multimap to hold the named parameters
MultiValueMap<String,String> parameters = new LinkedMultiValueMap<String,String>();
parameters.add("username", marshalRequest(usernameObj));
parameters.add("password", marshalRequest(passwordObj));
// Create the http entity for the request
HttpEntity<MultiValueMap<String,String>> entity =
new HttpEntity<MultiValueMap<String, String>>(parameters, headers);
// Get the response as a string
String response = rt.postForObject(endpoint, entity, String.class);
// Unmarshal the response back to the expected object
MyReturnObj obj = (MyReturnObj) unmarshalResponse(response);
This solution has allowed me to control how the object is marshalled/unmarshalled and simply posts strings instead of allowing Spring to handle the object directly. Its helped immensely!
这个解决方案使我能够控制对象的编组/解组方式，并简单地发布字符串，而不是让 Spring 直接处理对象。它的帮助非常大！
回答by Zaw Than oo
For Client Side
对于客户端
To pass the object as json string, use MappingHymanson2HttpMessageConverter.
要将对象作为 json 字符串传递，请使用MappingHymanson2HttpMessageConverter.
RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(new MappingHymanson2HttpMessageConverter());
For Server Sidespring configuration
对于服务器端弹簧配置
<bean class="org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter">
<property name="messageConverters">
<list>
<ref bean="jsonMessageConverter"/>
</list>
</property>
</bean>
<bean id="jsonMessageConverter" class="org.springframework.http.converter.json.MappingHymanson2HttpMessageConverter"/>
