jQuery 的元素或类 LIKE 选择器？
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Element or class LIKE selector for jQuery?
提问by David Andersson
For whatever reason I have these classes called .main_sub1, .main_sub2etc. Never mind why I can't have .main .sub.
无论出于何种原因，我有叫这些类.main_sub1，.main_sub2等你别管了，为什么我不能有.main .sub。
Is there a way with jQuery, sort of in the way it is possible to do with attributes, to get the classes containing main?
jQuery 有没有办法，有点像处理属性的方式，来获取包含 的类main？
回答by Tatu Ulmanen
Using $("[class^=main]")will select all elements whose classname starts with'main'. Take a look at jQuery docs about selectors, there are a lot of other variations you can use, for example:
Using$("[class^=main]")将选择所有类名以“main”开头的元素。看看关于 selectors 的 jQuery 文档，你可以使用很多其他的变体，例如：
[class*=main]will select elements whose classname contains'main'[class~=main]will select elements whose classname has the word'main' (delimited with spaces)[class$=main]will select elements whose classname ends in'main'
[class*=main]将选择类名包含“main”的元素[class~=main]将选择类名包含“main”一词的元素（用空格分隔）[class$=main]将选择类名以“main”结尾的元素
回答by Jimmy Cuadra
Yes, you can use an attribute selector to match certain values for the classattribute.
是的，您可以使用属性选择器来匹配属性的某些值class。
$('[class^=main]') // class begins with "main"
$('[class*=main]') // class contains "main" anywhere within it
回答by James Wiseman
In this instance, I would just treat the class attribute in the same way as you do a standard attribute.
在这种情况下，我只会像对待标准属性一样对待 class 属性。
$("[class*=main]")
