jQuery - 在对象数组中查找不同的值
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jQuery - Finding Distinct Values in Object Array
提问by Dexter
I've got an array of objects where each object has fields like title, description, family, etc. How can I perform a jQuery operation that grabs all objects in this array with a unique family name - similar to SQL's DISTINCT clause?
我有一个对象数组，其中每个对象都有标题、描述、系列等字段。我如何执行 jQuery 操作来获取该数组中具有唯一系列名称的所有对象 - 类似于 SQL 的 DISTINCT 子句？
回答by Nicola Peluchetti
You could do:
你可以这样做：
var array = [{
familyName: "one"},
{
familyName: "two"},
{
familyName: "one"},
{
familyName: "two"}];
var dupes = {};
var singles = [];
$.each(array, function(i, el) {
if (!dupes[el.familyName]) {
dupes[el.familyName] = true;
singles.push(el);
}
});
Singles is an array with only DISTINCT objects
Singles 是一个只有 DISTINCT 对象的数组
EDIT - i have blogged about this and given a more elaborate answer http://newcodeandroll.blogspot.it/2012/01/how-to-find-duplicates-in-array-in.html
编辑 - 我已经写了关于这个的博客并给出了一个更详细的答案http://newcodeandroll.blogspot.it/2012/01/how-to-find-duplicates-in-array-in.html
