java 如何正确设置 Content-Type？
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How to set Content-Type correctly?
提问by user996505
I want to change Content-Type but it dose not work...right? code:
我想更改 Content-Type 但它不起作用......对吗？代码：
HttpURLConnection conn=(HttpURLConnection)url.openConnection();
conn.setRequestProperty("Content-Type", "text/plain; charset=utf-8");
System.out.println(conn.getContentType());
the output is not "text/plain; charset=utf-8"...anything wrong? Thanks
输出不是“text/plain; charset=utf-8”...有什么问题吗？谢谢
采纳答案by laz
The value of getContentType()returns the value of the Content-Typeheader from the response, not the value set on the request. See the Javadoc I linked to. What exactly are you trying to do?
的值从响应getContentType()返回Content-Type标头的值，而不是在请求上设置的值。请参阅我链接到的 Javadoc。你到底想做什么？
回答by Steven Schlansker
As laz correctly points out, setting Content-Typeon the outgoing request isn't going to control the Content-Typeyou are going to get back on the response. If you have a server which is smart enough to dynamically control the Content-Typethe correct way to request a specific one is via an Accept header.
正如 laz 正确指出的那样，Content-Type对传出请求的设置不会控制Content-Type您将要返回的响应。如果您有一台足够智能的服务器，可以动态控制Content-Type请求特定服务器的正确方式，那就是通过Accept 标头。
The Accept request-header field can be used to specify certain media types which are acceptable for the response. The example
Accept: audio/*; q=0.2, audio/basicSHOULD be interpreted as "I prefer audio/basic, but send me any audio type if it is the best available after an 80% mark-down in quality."
Accept 请求头字段可用于指定响应可接受的某些媒体类型。这个例子
Accept: audio/*; q=0.2, audio/basic应该被解释为“我更喜欢音频/基本，但如果在质量下降 80% 后它是最好的，请给我发送任何音频类型。”
