java SocketTimeoutException：接受超时
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SocketTimeoutException: Accept timed out
提问by user555641
The following bit of code throws java.net.SocketTimeoutException: Accept timed out:
以下代码抛出java.net.SocketTimeoutException: Accept timed out：
ServerSocket serverSocket = new ServerSocket(0, 1, InetAddress.getLocalHost());
serverSocket.setSoTimeout(6000);
serverSocket.accept();
I have tried changing everything I can in creating a ServerSocketbut the error remains the same. Please guide me in what I'm missing here, if anything.
我尝试在创建 a 时更改我所能做的一切，ServerSocket但错误仍然相同。如果有的话，请指导我在这里缺少什么。
回答by Stephen C
What your code is doing is listening for 6 seconds for incoming TCP/IP requests on port zero for the local host1.
您的代码正在为本地主机1 的端口 0 上的传入 TCP/IP 请求监听 6 秒。
Here are some reasons why you might get a SocketTimeoutException.
以下是您可能会获得SocketTimeoutException.
- Nothing tries to connect to your service within the 6 second timeframe.
- Something tries to connect, but it is trying to connect on the wrong port. (Port zero sounds to me like you are trying to accept requests on "any" port, and I think that is unlikely to work.)
- There is a software or hardware firewall (or packet filter) that is preventing connection requests from reaching your application, or is blocking the replies.
- 在 6 秒的时间范围内没有任何尝试连接到您的服务。
- 有些东西试图连接，但它试图连接到错误的端口。（在我看来，零端口听起来像是您试图接受“任何”端口上的请求，我认为这不太可能奏效。）
- 有软件或硬件防火墙（或数据包过滤器）阻止连接请求到达您的应用程序，或阻止回复。
1 - If you don't want that "only accept an exception if it arrives within 6 seconds" behaviour ... which strikes me as a bit odd ... you shouldn't set a timeout on the server socket object.
1 - 如果您不希望“仅接受在 6 秒内到达的异常”行为……这让我觉得有点奇怪……您不应该在服务器套接字对象上设置超时。
