C# 将主机名解析为 IP
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Resolve HostName to IP
提问by Ba7a7chy
I have been through a lot of googling for this, I found a lot of examples none of which was working for me. This is a simple issue which I feel has a simple answer without defining new classes\modules etc...
我为此进行了很多谷歌搜索，我发现了很多例子，但没有一个对我有用。这是一个简单的问题，我觉得它有一个简单的答案，无需定义新的类\模块等...
My code is this :
我的代码是这样的：
Console.WriteLine ("Please enter an IP address or hostname");
string host = Console.ReadLine ();
***IP = resolved "host"***
Socket s = new Socket (AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);
s.Connect (IP, 80);
s.close();
How do I actually resolve the IP variable?
我如何实际解析 IP 变量？
采纳答案by Kolja
You can simply use the DNSclass to do so:
您可以简单地使用DNS类来执行此操作：
IPHostEntry hostEntry;
hostEntry= Dns.GetHostEntry(host);
//you might get more than one ip for a hostname since
//DNS supports more than one record
if (hostEntry.AddressList.Length > 0)
{
var ip = hostEntry.AddressList[0];
Socket s = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);
s.Connect(ip, 80);
}
回答by py2020
回答by PiotrK
Please take the note that accepted answer can resolve to IPv6. I attempted to connect to service that does not accept IPv6 as input string.
请注意，接受的答案可以解析为 IPv6。我试图连接到不接受 IPv6 作为输入字符串的服务。
Therefore try this snippet if you care to get IPv4:
因此，如果您想获得 IPv4，请尝试使用此代码段：
using System.Linq;
string host = "google.com";
Dns.GetHostEntry(host).AddressList.First(addr => addr.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork)
回答by marsh-wiggle
This is the method I use to resolve a hostname to IPv4 and / or IPv6.
这是我用来将主机名解析为 IPv4 和/或 IPv6 的方法。
using System.Net:
// A host can have multiple IP addresses!
public static IPAddress[] GetIPsByName(string hostName, bool ip4Wanted, bool ip6Wanted)
{
// Check if the hostname is already an IPAddress
IPAddress outIpAddress;
if (IPAddress.TryParse(hostName, out outIpAddress) == true)
return new IPAddress[] { outIpAddress };
//<----------
IPAddress[] addresslist = Dns.GetHostAddresses(hostName);
if (addresslist == null || addresslist.Length == 0)
return new IPAddress[0];
//<----------
if (ip4Wanted && ip6Wanted)
return addresslist;
//<----------
if (ip4Wanted)
return addresslist.Where(o => o.AddressFamily == AddressFamily.InterNetwork).ToArray();
//<----------
if (ip6Wanted)
return addresslist.Where(o => o.AddressFamily == AddressFamily.InterNetworkV6).ToArray();
//<----------
return new IPAddress[0];
}
