Javascript 使用多维数组创建多维对象
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Create multidimensional object with multidimensional arrays
提问by Kasper Skov
Im trying to build a somewhat advanced "Flot" jQuery pluging graph. For that, I need a multidimensional object (or at least I think it is).
我正在尝试构建一个有点高级的“Flot”jQuery 插件图。为此，我需要一个多维对象（或者至少我认为是）。
The structure should look like this:
结构应如下所示：
var datasets = {
"usa": {
label: "USA",
data: [[1988, 483994], [1989, 479060], [1990, 457648], [1991, 401949], [1992, 424705], [1993, 402375], [1994, 377867], [1995, 357382], [1996, 337946], [1997, 336185], [1998, 328611], [1999, 329421], [2000, 342172], [2001, 344932], [2002, 387303], [2003, 440813], [2004, 480451], [2005, 504638], [2006, 528692]]
},
"russia": {
label: "Russia",
data: [[1988, 218000], [1989, 203000], [1990, 171000], [1992, 42500], [1993, 37600], [1994, 36600], [1995, 21700], [1996, 19200], [1997, 21300], [1998, 13600], [1999, 14000], [2000, 19100], [2001, 21300], [2002, 23600], [2003, 25100], [2004, 26100], [2005, 31100], [2006, 34700]]
}
};
From my code-behind i've generated some lists looking like this (Not the same data, but dont mind that):
从我的代码隐藏中，我生成了一些看起来像这样的列表（不是相同的数据，但不要介意）：
<ul id="MOBILISATION">
<li data-key="2012/3/27">02:10</li>
<li data-key="2012/3/28">05:25</li>
<li data-key="2012/3/29">09:21</li>
<li data-key="2012/3/30">00:00</li>
<li data-key="2012/3/31">00:00</li>
</ul>
<ul id="OPERATIONS">
<li data-key="2012/3/27">19:51</li>
<li data-key="2012/3/28">18:35</li>
<li data-key="2012/3/29">14:39</li>
<li data-key="2012/3/30">07:46</li>
<li data-key="2012/3/31">10:26</li>
</ul>
Where "USA/usa" is "MOBILISATION", "1988" is "2012/3/27" and "483994" is "02:10". You get picture!!??
其中“USA/usa”是“MOBILISATION”，“1988”是“2012/3/27”，“483994”是“02:10”。有图吗！！！？
I've tried writing some jQuery, but it obviously doesnt work:
我试过写一些 jQuery，但它显然不起作用：
var objects = [];
var array = [];
var categoryName = "";
$('div#Container ul').each(function () {
catName = $(this).attr('id');
$('li', this).each(function () {
array.push([new Date($(this).data('key')).getTime(), $(this).text()]);
});
objects.push({ categoryName: { label: categoryName, data: array} });
});
var datasets = objects;
As you can see i've used push to objectsarray. Clearly thats not giving me the result I want. Im kindda loosing whats up and down in this, as its the first time im working with javascript/jQuery objects.
Whats the best solution for this?
如您所见，我使用了推送到objects数组。显然那没有给我我想要的结果。我有点失去了这方面的东西，因为这是我第一次使用 javascript/jQuery 对象。什么是最好的解决方案？
采纳答案by Bergi
Your datasets is an object, not an array - you can't push to it. Also, your variable categoryNamedoes not work like that (read more on dot and bracket notation). Try this:
你的数据集是一个对象，而不是一个数组——你不能推送到它。此外，您的变量categoryName不会像那样工作（阅读更多关于点和括号表示法）。尝试这个：
var datasets = {};
$('div#Container ul').each(function () {
catName = this.id;
var array = [];
$('li', this).each(function () {
array.push([
new Date($(this).data('key')).getTime(),
$(this).text()
]);
});
datasets[catName.toLowercase()] = {
label: catName.toUppercase(),
data: array
};
});
Also, I'm not sure whether you really would need to create Dateobjects, but that depends on your in- and output format.
另外，我不确定您是否真的需要创建Date对象，但这取决于您的输入和输出格式。
回答by Joe Green
Change var objects = [];to var objects = {};and change
更改var objects = [];到var objects = {};与变化
objects.push({ categoryName: { label: categoryName, data: array} });
to
到
objects[categoryName] = { label: categoryName, data: array};
The problem you have with JSON objects is in setting properties with a variable index. Yuo can use array notation to do that, as above.
JSON 对象的问题在于使用变量索引设置属性。Yuo 可以使用数组表示法来做到这一点，如上所述。
回答by Utkanos
Try
尝试
var data = {};
$('div#Container ul').each(function() {
var sub_obj = data[$(this).attr('id').toLowerCase()] = {
label: $(this).attr('id').toUpperCase(),
data: []
};
$(this).children('li').each(function() {
sub_obj.data.push([$(this).data('key'), $(this).text()]);
});
});
console.log(data);
回答by user10170700
function convertObject(obj, key) {
let returnObje = {};
if (!key) key = "";
else key = key + "_";
Object.keys(obj).forEach(function (k1) {
if (obj[k1] != null && typeof obj[k1] == "object") {
returnObje = Object.assign({}, returnObje, convertObject(obj[k1], key + k1))
} else
returnObje[key + k1] = obj[k1];
});
return returnObje;
}
var hotels = {
"hilton": {"name": "hilton hotel" },
"newton": {"name": "newton hotel"}
};
convertObject(hotels);
