ios 访问 NSArray 的元素及其索引
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acess element of NSArray with its index
提问by sreejith.virgo
Is it possible to access elements of an NSArraybased on index and use them for comparison/operations?
是否可以访问NSArray基于索引的元素并将它们用于比较/操作？
Just like arrayName[ith element]in C/C++
就像arrayName[ith element]在 C/C++ 中一样
回答by Toseef Khilji
Yes, you can access elements of an NSArray based on index .
是的，您可以根据索引访问 NSArray 的元素。
NSArray *a=@[@"s1",@"s2",@"s3"];
NSLog(@"%@",a[1]);
回答by Jay Gajjar
Try this
尝试这个
arrayName[yourIndex];
or
或者
[arrayName objectAtIndex:yourIndex];
回答by Kiattisak Anoochitarom
You can use 'Index Subscripting Literal' that Apple Provide on iOS 6 SDK later
您可以稍后在 iOS 6 SDK 上使用 Apple 提供的“索引下标文字”
NSArray *array = @[1, 2, 3];
NSLog(@"%@", array[0])
回答by user1673099
Try this way.
试试这个方法。
[arrayname objectAtindex:yourIndex]
[arrayname objectAtindex:yourIndex]
