php 语法错误,意外的 T_ENCAPSED_AND_WHITESPACE,需要 T_STRING 或 T_VARIABLE 或 T_NUM_STRING

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时间:2020-08-26 04:36:48  来源:igfitidea点击:

syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING

phpparsingsyntax

提问by user1083482

I have been staring at this code for hours now and I cannot figure out where my mistake is. I know this syntax error usually comes up because of some missing or out of place curly brace or some issue with single/double quotes and I'm not sure there is one anywhere in my code. I am only trying to fix my syntax right now so I can get the code to completely compile. Any help would be much appreciated. Here is my code:

我已经盯着这个代码几个小时了,我不知道我的错误在哪里。我知道这个语法错误通常是由于缺少或不合适的大括号或单/双引号的一些问题而出现的,我不确定我的代码中是否有任何地方。我现在只是想修复我的语法,这样我就可以让代码完全编译。任何帮助将非常感激。这是我的代码:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> 
<head> 
<title>Add to and Read from the Database</title>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1" />
</head> 
<body>

<?php
function print_form() {
echo <<<END
         <form action="$_SERVER[PHP_SELF]" method="post">

    <h3>Please put your comments below.</h3>

<input type="hidden" name="stage" value="process" >
<p>Name:</p>
<input type="text" size="30" name="WholeName" />
<p>Comment:</p>
<input type="text" size="200" name="Comment" />

<input type ="submit"  value ="Submit" >
</form>
END;    

    }
function process_form() {

print "<p>adding comment...</p>";

$Name = $_POST['WholeName'];
$Comment = $_POST['Comment'];

    if( preg_match("^[a-zA-Z]+$", $Name)) {
        if( preg_match("^[a-zA-Z0-9]_\-\'[.?!]+$", $Comment)) {
            $sql = "insert into comments1 values ( 
           '$Name', 
           '$Comment')";
           $result = mysql_query($sql) or die("Mysql query failed");
      } else {
        print "invalid name";
        }
  } else {
print "invalid characters";
 }

}

$db = mysql_connect("", "", "");
if (!$db) {
   print "Error - Could not connect to mysql";
   exit;
}  

$er = mysql_select_db("");
if (!$er) {
  print "Error - Could not connect to comments1 database";
  exit;
}

if (isset($_POST['stage']) && ('process' == $_POST['stage'])) {
   process_form();
} else {
    print_form();
}

?>

</body>
</html>

回答by JGurtz

I stumbled on this question as I had the same error. Mine was due to a slightly different problem and since I resolved it on my own I thought it useful to share here. Original code with issue:

我偶然发现了这个问题,因为我有同样的错误。我是由于一个稍微不同的问题,因为我自己解决了它,所以我认为在这里分享很有用。有问题的原始代码:

$comment = "$_POST['comment']";

Because of the enclosing double-quotes, the index is not dereferenced properly leading to the assignment error. In my case I chose to fix it like this:

由于包含双引号,索引未正确解除引用导致分配错误。在我的情况下,我选择这样修复它:

$comment = "$_POST[comment]";

but dropping either pair of quotes works; it's a matter of style I suppose :)

但是删除任何一对引号都有效;我想这是一个风格问题:)

回答by deceze

Your problem is that you're not closing your HEREDOC correctly. The line containing END;must not contain any whitespace afterwards.

您的问题是您没有正确关闭 HEREDOC。包含的行END;之后不得包含任何空格

回答by Toto

You have extra spaces after END;that cause the heredoc not terminated.

之后您有额外的空格END;,导致heredoc 未终止。

回答by mat

Might be a pasting problem, but as far as I can see from your code, you're missing the single quotes around the HTML part you're echo-ing.

可能是粘贴问题,但就我从您的代码中看到的而言,您缺少回显的 HTML 部分周围的单引号。

If not, could you post the code correctly and tell us what line is causing the error?

如果没有,您能否正确发布代码并告诉我们哪一行导致错误?