使用参数调用函数的 Bash 脚本“if”语句
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Bash script 'if' statement that calls a function with parameters
提问by user265330
I want an if statement in my bash script that does:
我想要在我的 bash 脚本中使用 if 语句：
if [[ "$v" == "A" || my_func $x $y ]] ; then
but I get the error "conditional binary operator expected". I've tried putting quotes round the parameters in the call to my_func, but still no good. Tried playing around with eval, which didn't help either.
但我收到错误“预期的条件二元运算符”。我试过在 my_func 调用中的参数周围加上引号，但仍然不好。尝试玩弄 eval，这也无济于事。
Thanks for any help.
谢谢你的帮助。
回答by kev
You can try:
你可以试试：
if [[ "$v" == "A" ]] || my_func $x $y ; then
