Java 是否有“每个”匹配器的 Hamcrest 断言集合或迭代器的所有元素匹配单个特定匹配器？
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Is there a Hamcrest "for each" Matcher that asserts all elements of a Collection or Iterable match a single specific Matcher?
提问by E-Riz
Given a Collectionor Iterableof items, is there any Matcher(or combination of matchers) that will assert every item matches a single Matcher?
给定一个Collection或Iterable多个项目，是否有任何Matcher（或匹配器组合）可以断言每个项目匹配一个Matcher？
For example, given this item type:
例如，给定此项目类型：
public interface Person {
public String getGender();
}
I'd like to write an assertion that all items in a collection of Persons have a specific gendervalue. I'm thinking something like this:
我想写一个断言，即Persons集合中的所有项目都具有特定gender值。我在想这样的事情：
Iterable<Person> people = ...;
assertThat(people, each(hasProperty("gender", "Male")));
Is there any way to do this without writing the eachmatcher myself?
有没有办法在不each自己编写匹配器的情况下做到这一点？
采纳答案by Sotirios Delimanolis
Use the Everymatcher.
使用Every匹配器。
import org.hamcrest.beans.HasPropertyWithValue;
import org.hamcrest.core.Every;
import org.hamcrest.core.Is;
import org.junit.Assert;
Assert.assertThat(people, (Every.everyItem(HasPropertyWithValue.hasProperty("gender", Is.is("male")))));
Hamcrest also provides Matchers#everyItemas a shortcut to that Matcher.
Hamcrest 还提供Matchers#everyItem了一个快捷方式Matcher。
Full example
完整示例
@org.junit.Test
public void method() throws Exception {
Iterable<Person> people = Arrays.asList(new Person(), new Person());
Assert.assertThat(people, (Every.everyItem(HasPropertyWithValue.hasProperty("gender", Is.is("male")))));
}
public static class Person {
String gender = "male";
public String getGender() {
return gender;
}
public void setGender(String gender) {
this.gender = gender;
}
}
回答by Markus
IMHO this is much more readable:
恕我直言，这更具可读性：
people.forEach(person -> Assert.assertThat(person.getGender()), Is.is("male"));
