xcode 显示/隐藏标签（带切换按钮）
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Show/Hide Label (w/ Toggle Button)
提问by Zakman411
I have an application I'm working on where I need a button (upon click) to show/hide a label. I set up the label as an IBOutlet, and the button as an IBAction - but don't really know where to go from here. I'm still very new to cocoa - I figure it's pretty simple but objective-c is daunting to me. Any help (in dummies terms)?
我有一个正在处理的应用程序，我需要一个按钮（单击时）来显示/隐藏标签。我将标签设置为 IBOutlet，将按钮设置为 IBAction - 但真的不知道从哪里开始。我对可可还是很陌生 - 我认为它很简单，但 Objective-c 对我来说是令人生畏的。有什么帮助（用假人的话）？
回答by Nikita Rybak
回答by Redauser
There is another way to do that. You can simply use the "dot notation", it works this way:
还有另一种方法可以做到这一点。您可以简单地使用“点符号”，它是这样工作的：
if(theLabel.hidden == YES) {
theLabel.hidden = NO;
}
else {
theLabel.hidden = YES;
}
回答by dylan
Swift 3.0
斯威夫特 3.0
In the Swift Syntax, you can perform the show/hide button as follows, with an updating title string to identify it's state:
在 Swift 语法中，您可以按如下方式执行显示/隐藏按钮，并使用更新的标题字符串来标识其状态：
if (string.isHidden == true) {
sender.title = "Hide"
string.isHidden = false
} else {
sender.title = "Show"
string.isHidden = true
}
回答by Ed Norris
Or this:
或这个：
theLabel.hidden = !theLabel.hidden
