Python 替换字符串中的所有非字母数字字符
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Replace all non-alphanumeric characters in a string
提问by tchadwik
I have a string with which i want to replace any character that isn't a standard character or number such as (a-z or 0-9) with an asterisk. For example, "h^&ell`.,|o w]{+orld" is replaced with "h*ell*o*w*orld". Note that multiple characters such as "^&" get replaced with one asterisk. How would I go about doing this?
我有一个字符串，我想用它替换任何不是标准字符或数字的字符，例如（az 或 0-9）用星号。例如，“h^&ell`.,|ow]{+orld”被替换为“h*ell*o*w*orld”。请注意，多个字符（例如“^&”）将替换为一个星号。我该怎么做呢？
采纳答案by nneonneo
Regex to the rescue!
正则表达式来救援！
import re
s = re.sub('[^0-9a-zA-Z]+', '*', s)
Example:
例子：
>>> re.sub('[^0-9a-zA-Z]+', '*', 'h^&ell`.,|o w]{+orld')
'h*ell*o*w*orld'
回答by baloan
The pythonic way.
蟒蛇式的方式。
print "".join([ c if c.isalnum() else "*" for c in s ])
This doesn't deal with grouping multiple consecutive non-matching characters though, i.e.
不过，这并不涉及对多个连续的不匹配字符进行分组，即
"h^&i => "h**inot "h*i"as in the regex solutions.
"h^&i => "h**i不像"h*i"在正则表达式解决方案中那样。
回答by Don
Try:
尝试：
s = filter(str.isalnum, s)
in Python3:
在 Python3 中：
s = ''.join(filter(str.isalnum, s))
Edit: realized that the OP wants to replace non-chars with '*'. My answer does not fit
编辑：意识到 OP 想要用“*”替换非字符。我的答案不合适
回答by psun
Use \Wwhich is equivalent to [^a-zA-Z0-9_]. Check the documentation, https://docs.python.org/2/library/re.html
使用\W等效于[^a-zA-Z0-9_]. 检查文档，https://docs.python.org/2/library/re.html
Import re
s = 'h^&ell`.,|o w]{+orld'
replaced_string = re.sub(r'\W+', '*', s)
output: 'h*ell*o*w*orld'
update: This solution will exclude underscore as well. If you want only alphabets and numbers to be excluded, then solution by nneonneo is more appropriate.
更新：此解决方案也将排除下划线。如果您只想排除字母和数字，则 nneonneo 的解决方案更合适。
