javascript Webpack:为目录中的每个文件创建一个包

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时间:2020-10-28 12:44:17  来源:igfitidea点击:

Webpack: Create a bundle with each file in directory

javascriptangularjswebpack

提问by alisabzevari

I am trying to bundle every angular module in webpack. My target is to have one app.js that will be bundled by webpack with this configuration:

我试图在 webpack 中捆绑每个 angular 模块。我的目标是拥有一个 app.js,它将被 webpack 与此配置捆绑在一起:

entry: {
        app: "./app/app.js"
},
output: {
        path: "./build/ClientBin",
        filename: "bundle.js"
},

I will place this bundle script in my index.html so it will entry point of my app. Also I have many modules in ./app/componentsfolder. Folder structure in like:

我将把这个包脚本放在我的 index.html 中,这样它就会成为我的应用程序的入口点。另外我在./app/components文件夹中有很多模块。文件夹结构如下:

app
|--components
|  |
|  |--home
|  |  |
|  |  |--home.html
|  |  |--home.js
|--app.js
|--AppController.js

I have required home.htmlin home.jsso when I load home.jsall of its needed files will load. The problem is I have several components like homeand I want to tell webpack to bundle each component separately and name it with its containing folder like home.

我有要求home.htmlhome.js所以当我加载home.js它需要的所有文件时都会加载。问题是我有几个组件,例如home,我想告诉 webpack 分别捆绑每个组件并使用其包含的文件夹命名它,例如home.

How can I config webpack to create these bundles and put them in ./build/components?

我如何配置 webpack 来创建这些包并将它们放入./build/components

采纳答案by alisabzevari

I ended up defining entries programmatically. I wrote this in my webpack.config.js:

我最终以编程方式定义了条目。我在我的 webpack.config.js 中写了这个:

function getDirectories(srcpath) {
    return fs.readdirSync(srcpath).filter(function (file) {
        return fs.statSync(path.join(srcpath, file)).isDirectory();
    });
}

var entry = {
    app: "./app/app.ts",
    vendor: ["angular", "oclazyload", "angular-new-router", "lodash"]
};
var components = getDirectories("./app/components");
for (var i = 0; i < components.length; i++) {
    entry[components[i]] = "./app/components/" + components[i] + "/" + components[i] + ".ts";
}

And then used entryvariable in config.

然后entry在配置中使用变量。

回答by David

A simpler way:

一个更简单的方法:

Use globs in your webpack.config.js:

在您的webpack.config.js: 中使用 globs

Here's an example:

下面是一个例子:

var glob = require("glob");

module.exports = {
  entry: {
     js: glob.sync("./app/components/**/*.js"),  
  }
}

回答by Juho Veps?l?inen

You can achieve what you want like this:

你可以像这样实现你想要的:

entry: {
    home: './app/app.js',
    page: './page/app.js',
},
output: {
    path: './build/ClientBin',
    filename: '[name].js',
},

This will generate home.jsand page.jsat your output path. Tweak, generalize as needed. You'll probably want to extract those entry paths to a variable and so on.

这将在您的输出路径中生成home.jspage.js。调整,根据需要进行概括。您可能希望将这些入口路径提取到变量等等。

Note that with a bit of tweaking you are likely able to output the bundles exactly where you want. I expect you would then use a pathlike ./app/components/[name]or so.

请注意,通过一些调整,您可能能够准确地将包输出到您想要的位置。我希望你会使用path类似的东西./app/components/[name]

回答by Acidic9

To have each file exported individually, you can use the following code snippet to do so:

要单独导出每个文件,您可以使用以下代码片段来执行此操作:

const glob = require('glob')
const path = require('path')

const entryFiles = glob.sync('./app/components/**/*.js').reduce((previousValue, currentValue, currentIndex, array) => {
  return typeof previousValue === 'string' ?
    {
      [path.basename(previousValue, path.extname(previousValue))]: previousValue,
      [path.basename(currentValue, path.extname(currentValue))]: currentValue
    }
    :
    { ...previousValue, [path.basename(currentValue, path.extname(currentValue))]: currentValue }
})

module.exports = {
  entry: entryFiles,
  resolve: {
    extensions: [ '.js' ]
  },
  output: {
    filename: '[name].js',
    path: path.resolve(__dirname, 'build', 'ClientBin')
  }
}