bash 如何在 Unix Shell 中遍历字符串中的每个字母
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How to iterate through each letter in a string in Unix Shell
提问by oliv
I am trying to iterate through a string taken as an input through the readcommand. I'm trying to output the number of each letter and each letter It should then use a loop to output each letter in turn. For example, if the user enters "picasso", the output should be:
我正在尝试通过读取命令遍历作为输入的字符串。我正在尝试输出每个字母和每个字母的编号，然后应该使用循环依次输出每个字母。例如，如果用户输入“毕加索”，则输出应为：
Letter 1: p Letter 2: i Letter 3: c Letter 4: a Letter 5: s Letter 6: s Letter 7: o
字母 1：p 字母 2：i 字母 3：c 字母 4：a 字母 5：s 字母 6：s 字母 7：o
Here is my current code:
这是我当前的代码：
#!/bin/bash
# Prompt a user to enter a word and output each letter in turn.
read -p "Please enter a word: " word
for i in $word
do
echo "Letter $i: $word"
done
Should I be placing the input to an array? I'm still new to programming loops but I'm finding it impossible to figure out the logic.
我应该将输入放入数组吗？我对编程循环还是个新手，但我发现无法弄清楚逻辑。
Any advice? Thanks.
有什么建议吗？谢谢。
回答by oliv
Combining answers from dtmilano and patrat would give you:
结合 dtmilano 和 patrat 的答案会给你：
read -p "Please enter a word: " word
for i in $(seq 1 ${#word})
do
echo "Letter $i: ${word:i-1:1}"
done
${#word} gives you the length of the string.
${#word} 为您提供字符串的长度。
回答by Diego Torres Milano
Use the substring operator
使用子串运算符
${word:i:1}
to obtain the i'th character of word.
获得单词的第 i 个字符。
回答by patrat
Check out seq mechanism in bash
查看 bash 中的 seq 机制
For example:
例如：
seq 1 10
Will give you
会给你
1 2 3 4 5 6 7 8 9 10
You can try with letters
你可以试试字母
echo {a..g}
Result
结果
a b c d e f g
Now you should handle your problem
现在你应该处理你的问题
