php 如何检查日期是否在给定范围内？

How to check if a date is in a given range?

提问by meleyal

If you have a $start_dateand $end_date, how can you check if a date given by the user falls within that range?

如果您有$start_dateand $end_date，您如何检查用户给出的日期是否在该范围内？

e.g.

例如

$start_date = '2009-06-17';

$end_date = '2009-09-05';

$date_from_user = '2009-08-28'; 

At the moment the dates are strings, would it help to convert them to timestamp integers?

目前日期是字符串，将它们转换为时间戳整数是否有帮助？

回答by ConroyP

Converting them to timestamps is the way to go alright, using strtotime, e.g.

将它们转换为时间戳是正确的方法，使用strtotime，例如

$start_date = '2009-06-17';

$end_date = '2009-09-05';

$date_from_user = '2009-08-28';

check_in_range($start_date, $end_date, $date_from_user);


function check_in_range($start_date, $end_date, $date_from_user)
{
  // Convert to timestamp
  $start_ts = strtotime($start_date);
  $end_ts = strtotime($end_date);
  $user_ts = strtotime($date_from_user);

  // Check that user date is between start & end
  return (($user_ts >= $start_ts) && ($user_ts <= $end_ts));
}

回答by spencer7593

It's not necessary to convert to timestamp to do the comparison, given that the strings are validated as dates in 'YYYY-MM-DD' canonical format.

没有必要转换为时间戳来进行比较，因为字符串被验证为 'YYYY-MM-DD' 规范格式的日期。

This test will work:

此测试将起作用：

( ( $date_from_user >= $start_date ) && ( $date_from_user <= $end_date ) )

given:

给出：

$start_date     = '2009-06-17';
$end_date       = '2009-09-05';
$date_from_user = '2009-08-28';

NOTE: Comparing strings like this does allow for "non-valid" dates e.g. (December 32nd ) '2009-13-32' and for weirdly formatted strings '2009/3/3', such that a string comparison will NOT be equivalent to a date or timestamp comparison. This works ONLY if the date values in the strings are in a CONSISTENTand CANONICALformat.

注意：像这样比较字符串确实允许“无效”日期，例如 (December 32nd ) '2009-13-32' 和格式奇怪的字符串 '2009/3/3'，这样字符串比较将不等同于日期或时间戳比较。仅当字符串中的日期值采用CONSISTENT和CANONICAL格式时才有效。

EDITto add a note here, elaborating on the obvious.

编辑以在此处添加注释，详细说明显而易见的内容。

By CONSISTENT, I mean for example that the strings being compared must be in identical format: the month must always be two characters, the day must always be two characters, and the separator character must always be a dash. We can't reliably compare "strings" that aren't four character year, two character month, two character day. If we had a mix of one character and two character months in the strings, for example, we'd get unexpected result when we compared, '2009-9-30'to '2009-10-11'. We humanly see "9" as being less than "10", but a string comparison will see '2009-9'as greater than '2009-1'. We don't necessarily need to have a dash separator characters; we could just as reliably compare strings in 'YYYYMMDD'format; if there is a separator character, it has to always be there and always be the same.

通过CONSISTENT，我的意思是，例如，被比较的字符串必须采用相同的格式：月份必须始终为两个字符，日期必须始终为两个字符，分隔符必须始终为破折号。我们无法可靠地比较不是四个字符的年份、两个字符的月份、两个字符的日期的“字符串”。如果我们有一个字符和字符串两种字符个月的混合，例如，我们希望当我们比较得到意想不到的结果，'2009-9-30'来'2009-10-11'。我们将“9”视为小于“10”，但字符串比较将'2009-9'视为大于'2009-1'。我们不一定需要有破折号分隔符；我们可以可靠地比较中的字符串'YYYYMMDD'格式; 如果有分隔符，它必须始终存在并且始终相同。

By CANONICAL, I mean that a format that will result in strings that will be sorted in date order. That is, the string will have a representation of "year" first, then "month", then "day". We can't reliably compare strings in 'MM-DD-YYYY'format, because that's not canonical. A string comparison would compare the MM(month) before it compared YYYY(year) since the string comparison works from left to right.) A big benefit of the 'YYYY-MM-DD' string format is that it is canonical; dates represented in this format can reliably be compared as strings.

通过CANONICAL，我的意思是一种将导致按日期顺序排序的字符串的格式。也就是说，字符串将首先表示“年”，然后是“月”，然后是“日”。我们无法可靠地比较'MM-DD-YYYY'格式中的字符串，因为这不是规范的。字符串比较会MM在比较YYYY（年）之前先比较（月），因为字符串比较是从左到右进行的。）'YYYY-MM-DD' 字符串格式的一大好处是它是规范的；以这种格式表示的日期可以可靠地作为字符串进行比较。

[ADDENDUM]

[附录]

If you do go for the php timestamp conversion, be aware of the limitations.

如果您确实要进行 php 时间戳转换，请注意限制。

On some platforms, php does not support timestamp values earlier than 1970-01-01 and/or later than 2038-01-19. (That's the nature of the unix timestamp 32-bit integer.) Later versions pf php (5.3?) are supposed to address that.

在某些平台上，php 不支持早于 1970-01-01 和/或晚于 2038-01-19 的时间戳值。（这是 unix 时间戳 32 位整数的性质。）更高版本的 pf php（5.3？）应该解决这个问题。

The timezone can also be an issue, if you aren't careful to use the same timezone when converting from string to timestamp and from timestamp back to string.

时区也可能是一个问题，如果您在从字符串转换为时间戳以及从时间戳转换回字符串时不小心使用相同的时区。

HTH

HTH

回答by oldwizard

Use the DateTime class if you have PHP 5.3+. Easier to use, better functionality.

如果您有 PHP 5.3+，请使用 DateTime 类。更容易使用，更好的功能。

DateTime internally supports timezones, with the other solutions is up to you to handle that.

DateTime 内部支持时区，其他解决方案由您来处理。

<?php    
/**
 * @param DateTime $date Date that is to be checked if it falls between $startDate and $endDate
 * @param DateTime $startDate Date should be after this date to return true
 * @param DateTime $endDate Date should be before this date to return true
 * return bool
 */
function isDateBetweenDates(DateTime $date, DateTime $startDate, DateTime $endDate) {
    return $date > $startDate && $date < $endDate;
}

$fromUser = new DateTime("2012-03-01");
$startDate = new DateTime("2012-02-01 00:00:00");
$endDate = new DateTime("2012-04-30 23:59:59");

echo isDateBetweenDates($fromUser, $startDate, $endDate);

回答by Stan R.

$startDatedt = strtotime($start_date)
$endDatedt = strtotime($end_date)
$usrDatedt = strtotime($date_from_user)

if( $usrDatedt >= $startDatedt && $usrDatedt <= $endDatedt)
{
   //..falls within range
}

回答by Glen

Convert both dates to timestamps then do

将两个日期都转换为时间戳，然后执行

pseudocode:

伪代码：

if date_from_user > start_date && date_from_user < end_date
    return true

回答by richardtallent

In the format you've provided, assuming the user is smart enough to give you valid dates, you don't need to convert to a date first, you can compare them as strings.

在您提供的格式中，假设用户足够聪明，可以为您提供有效日期，您不需要先转换为日期，您可以将它们作为字符串进行比较。

回答by Paulo Henrique

$start_date="17/02/2012";
$end_date="21/02/2012";
$date_from_user="19/02/2012";

function geraTimestamp($data)
{
    $partes = explode('/', $data); 
    return mktime(0, 0, 0, $partes[1], $partes[0], $partes[2]);
}


$startDatedt = geraTimestamp($start_date); 
$endDatedt = geraTimestamp($end_date);
$usrDatedt = geraTimestamp($date_from_user);

if (($usrDatedt >= $startDatedt) && ($usrDatedt <= $endDatedt))
{ 
    echo "Dentro";
}    
else
{
    echo "Fora";
}

回答by TheTXI

Convert them into dates or timestamp integers and then just check of $date_from_user is <= $end_date and >= $start_date

将它们转换为日期或时间戳整数，然后只需检查 $date_from_user 是 <= $end_date 和 >= $start_date

回答by Ilya

You can try this:

你可以试试这个：

//custom date for example
$d1 = new DateTime("2012-07-08");
$d2 = new DateTime("2012-07-11");
$d3 = new DateTime("2012-07-08");
$d4 = new DateTime("2012-07-15");

//create a date period object
$interval = new DateInterval('P1D');
$daterange = iterator_to_array(new DatePeriod($d1, $interval, $d2));
$daterange1 = iterator_to_array(new DatePeriod($d3, $interval, $d4));
array_map(function($v) use ($daterange1) { if(in_array($v, $daterange1)) print "Bingo!";}, $daterange);

回答by iniravpatel

I found this method the easiest:

我发现这个方法最简单：

$start_date = '2009-06-17';
$end_date = '2009-09-05';
$date_from_user = '2009-08-28';

$start_date = date_create($start_date);
$date_from_user = date_create($date_from_user);
$end_date = date_create($end_date);

$interval1 = date_diff($start_date, $date_from_user);
$interval2 = date_diff($end_date, $date_from_user);

if($interval1->invert == 0){
  if($interval2->invert == 1){

     // if it lies between start date and end date execute this code

  }
}