使用java更新json对象
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updating json object using java
提问by
Let i've an JSONObject like as shown below
让我有一个JSON如下所示的对象
{"Name":"Manu","Age":"25","Address":""}
Updation
更新
Read the json object and need to update the address field like as given below
读取 json 对象并需要更新地址字段，如下所示
{"Name":"Manu","Age":"25","Address":"XXXX"}
can anyone please tell me how to update the Address details in the JSONusing java
谁能告诉我如何更新的详细地址JSON使用java
My code
我的代码
JSONObject rec = new JSONObject(data);
String name = rec.getString("Name");
String age = rec.getString("Age");
String add = rec.getString("Address");
now how to add some information to the address field
现在如何向地址字段添加一些信息
Update 1
更新 1
String jsonstring="{Name:Manu,Age:25,Address:''}";
JSONObject object=new JSONObject(jsonstring);
JSONObject childobject=object.getJSONObject("Address");
JSONObject modifiedjson=new JSONObject();
modifiedjson.put("type",childobject.get("type"));
modifiedjson.put("value","newvalue");
Exception
例外
Exception in thread "main" org.json.JSONException: JSONObject["Address"] is not a JSONObject.
at org.json.JSONObject.getJSONObject(JSONObject.java:557)
at kotouch.Sample.main(Sample.java:59)
Java Result: 1
回答by Nasruddin
Parse the JSON and call the particular Key needs to be updated and set the value for the key. Please be more specific.
解析 JSON 并调用需要更新的特定 Key 并设置该键的值。请更具体。
Create a new JSON Object
创建一个新的 JSON 对象
private JSONObject Data = new JSONObject;
public Test(){
try {
Data.put("address", username);
}
catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
回答by Rawa
If you are using the JsonObject classit is immutable
如果您使用的是JsonObject 类，它是不可变的
So i believe you have to duplicate the object and change the value like this:
所以我相信你必须复制对象并像这样更改值：
JSONObject object=new JSONObject(jsonstring);
JSONObject childobject=object.getJSONObject("XXXX");
JSONObject modifiedjson=new JSONObject();
modifiedjson.put("type",childobject.get("type"));
modifiedjson.put("value","newvalue"); // Add new value of XXXX here
