在单独的线程中启动 WPF 窗口
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Launching a WPF Window in a Separate Thread
提问by Cyberguille
I'm using the following code for to open a window in a separate thread
我正在使用以下代码在单独的线程中打开一个窗口
public partial class App : Application
{
protected override void OnStartup(StartupEventArgs e)
{
base.OnStartup(e);
}
private void button1_Click(object sender, RoutedEventArgs e)
{
Thread newWindowThread = new Thread(new ThreadStart(() =>
{
// Create and show the Window
Config tempWindow = new Config();
tempWindow.Show();
// Start the Dispatcher Processing
System.Windows.Threading.Dispatcher.Run();
}));
// Set the apartment state
newWindowThread.SetApartmentState(ApartmentState.STA);
// Make the thread a background thread
newWindowThread.IsBackground = true;
// Start the thread
}
}
If I use this code in a method, it works. But when I use it as follows, I get an error:
如果我在方法中使用此代码，它会起作用。但是当我按如下方式使用它时，出现错误：
public partial class App : Application
{
#region Instance Variables
private Thread newWindowThread;
#endregion
protected override void OnStartup(StartupEventArgs e)
{
base.OnStartup(e);
newWindowThread = new Thread(new ThreadStart(() =>
{
// Create and show the Window
Config tempWindow = new Config();
tempWindow.Show();
// Start the Dispatcher Processing
System.Windows.Threading.Dispatcher.Run();
}));
}
private void button1_Click(object sender, RoutedEventArgs e)
{
// Set the apartment state
newWindowThread.SetApartmentState(ApartmentState.STA);
// Make the thread a background thread
newWindowThread.IsBackground = true;
// Start the thread
}
}
It throws the following error:
它引发以下错误：
System.Threading.ThreadStateException
The state of the thread was not valid to execute the operation
What is the cause of this?
这是什么原因？
采纳答案by Cyberguille
@d.moncada, @JPVenson, @TomTom sorry for everyone, espetially to @d.moncada, your answer made me realize my true error, indeed if run once until my code works. But my really problem is that i try to push button1_Click in two ocation, really i take a timer that called a method with the line of the
@d.moncada、@JPVenson、@TomTom 对不起大家，尤其是@d.moncada，你的回答让我意识到我真正的错误，如果运行一次直到我的代码工作。但是我真正的问题是我尝试在两个位置按下 button1_Click，实际上我使用了一个计时器，该计时器使用了
private void button1_Click(object sender, RoutedEventArgs e)
Now the solution of my problem is Detecting a Thread is already running in C# .net?
现在我的问题的解决方案是检测线程是否已经在 C# .net 中运行？
回答by d.moncada
I believe the problem is that you are setting the ApartmentStateafter the Threadas started running.
我认为，问题是，你正在设置ApartmentState后Thread的开始运行。
Try:
尝试：
public partial class App : Application
{
#region Instance Variables
private Thread newWindowThread;
#endregion
protected override void OnStartup(StartupEventArgs e)
{
base.OnStartup(e);
newWindowThread = new Thread(new Thread(() =>
{
// Create and show the Window
Config tempWindow = new Config();
tempWindow.Show();
// Start the Dispatcher Processing
System.Windows.Threading.Dispatcher.Run();
}));
// Set the apartment state
newWindowThread.SetApartmentState(ApartmentState.STA);
// Make the thread a background thread
newWindowThread.IsBackground = true;
}
private void button1_Click(object sender, RoutedEventArgs e)
{
// Start the thread
newWindowThread.Start();
}
}
回答by Venson
why you trying to do this? there is (nearly)no reason to run a 2end UI thread inside you application ... if you want a non Modal new Window, instantiate you window and call show.
你为什么要这样做？（几乎）没有理由在您的应用程序中运行 2end UI 线程……如果您想要一个非模态新窗口，请实例化您的窗口并调用show.
Why nearly? Because this is a very complex topic and unless you have a huge budged to develop exactly this behavior, you can live without it.
为什么差不多？因为这是一个非常复杂的话题，除非你有很大的预算来发展这种行为，否则你可以没有它。
