string 如何在Scala中将字符串拆分为字符
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How to split strings into characters in Scala
提问by sam
For example, there is a string val s = "Test". How do you separate it into t, e, s, t?
例如，有一个字符串 val s = "Test"。你怎么把它分成t, e, s, t？
回答by Rex Kerr
Do you need characters?
你需要人物吗？
"Test".toList // Makes a list of characters
"Test".toArray // Makes an array of characters
Do you need bytes?
你需要字节吗？
"Test".getBytes // Java provides this
Do you need strings?
你需要字符串吗？
"Test".map(_.toString) // Vector of strings
"Test".sliding(1).toList // List of strings
"Test".sliding(1).toArray // Array of strings
Do you need UTF-32 code points? Okay, that's a tougher one.
您需要 UTF-32 代码点吗？好吧，那是更难的。
def UTF32point(s: String, idx: Int = 0, found: List[Int] = Nil): List[Int] = {
if (idx >= s.length) found.reverse
else {
val point = s.codePointAt(idx)
UTF32point(s, idx + java.lang.Character.charCount(point), point :: found)
}
}
UTF32point("Test")
回答by aioobe
You can use toListas follows:
您可以toList按如下方式使用：
scala> s.toList
res1: List[Char] = List(T, e, s, t)
If you want an array, you can use toArray
如果你想要一个数组，你可以使用 toArray
scala> s.toArray
res2: Array[Char] = Array(T, e, s, t)
回答by tenshi
Actually you don't need to do anything special. There is already implicit conversion in Predefto WrappedStringand WrappedStringextends IndexedSeq[Char]so you have all goodies that available in it, like:
其实你不需要做任何特别的事情。已经有隐式转换Predef到WrappedString和WrappedString扩展，IndexedSeq[Char]所以你有所有可用的东西，比如：
"Test" foreach println
"Test" map (_ + "!")
Edit
编辑
Predefhas augmentStringconversion that has higher priority than wrapStringin LowPriorityImplicits. So String end up being StringLike[String], that is also Seqof chars.
Predef具有augmentString比wrapStringin更高优先级的转换LowPriorityImplicits。所以 String 最终是StringLike[String]，那也是Seq字符。
回答by Dave Griffith
Additionally, it should be noted that if what you actually want isn't an actual list object, but simply to do something which each character, then Strings can be used as iterable collections of characters in Scala
此外，应该注意的是，如果您真正想要的不是实际的列表对象，而只是对每个字符执行某些操作，那么字符串可以用作 Scala 中的可迭代字符集合
for(ch<-"Test") println("_" + ch + "_") //prints each letter on a different line, surrounded by underscores
