java 将 ArrayList 转换为 JSON - Android
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Converting ArrayList to JSON - Android
提问by user3800832
I have a Array List and a separate string. i want to convert these into JSON format and expect it below json format.
我有一个数组列表和一个单独的字符串。我想将这些转换为 JSON 格式并期望它低于 json 格式。
Expected format,
预期格式，
{
"last_sync_date": "2014-06-30 04:47:45",
"recordset": [
{
"contact_group": {
"guid": "y37845y8y",
"name": "Family",
"description": "Family members",
"isDeleted": 0
}
},
{
"contact_group": {
"guid": "gt45tergh4",
"name": "Office",
"description": "Office members",
"isDeleted": 0
}
}
]
}
i used this way bt it's wrong,
我是这样用的，但这是错误的，
public void createGroupInServer(Activity activity, String lastSyncDateTime, ArrayList<ContactGroup> groups)
throws JSONException {
// create json object to contact group
JSONObject syncDateTime = new JSONObject();
syncDateTime.putOpt("last_sync_date", lastSyncDateTime);
JSONArray jsArray = new JSONArray("recordset");
for (int i=0; i < groups.size(); i++) {
JSONObject adsJsonObject = new JSONObject("contact_group");
adsJsonObject = jsArray.getJSONObject(i);
adsJsonObject.put("guid", groups.get(i).getGroupId());
adsJsonObject.put("name", groups.get(i).getGroupName());
adsJsonObject.put("isDeleted", groups.get(i).getIsDeleted());
}
please help.
请帮忙。
回答by Stephen C
You are mostly on the right track ... but there are a few mistakes:
你大部分都在正确的轨道上......但有一些错误：
public JSONObject createGroupInServer(
Activity activity, String lastSyncDateTime,
ArrayList<ContactGroup> groups)
throws JSONException {
JSONObject jResult = new JSONObject();
jResult.putOpt("last_sync_date", lastSyncDateTime);
JSONArray jArray = new JSONArray();
for (int i = 0; i < groups.size(); i++) {
JSONObject jGroup = new JSONObject();
jGroup.put("guid", groups.get(i).getGroupId());
jGroup.put("name", groups.get(i).getGroupName());
jGroup.put("isDeleted", groups.get(i).getIsDeleted());
// etcetera
JSONObject jOuter = new JSONObject();
jOuter.put("contact_group", jGroup);
jArray.put(jOuter);
}
jResult.put("recordset", jArray);
return jResult;
}
But I agree with the other Answers that suggest you use a "mapping" technology like GSON rather than coding this by hand. Especially if this gets more complicated.
但我同意其他答案，建议您使用像 GSON 这样的“映射”技术，而不是手动编码。特别是如果这变得更加复杂。
回答by Paras Mittal
You could use GSON.
你可以使用 GSON。
It provides a lot of functionality and its very simple to use.
它提供了很多功能并且使用起来非常简单。
Have a look at these examples.
看看这些例子。
http://kylewbanks.com/blog/Tutorial-Android-Parsing-JSON-with-GSON
http://kylewbanks.com/blog/Tutorial-Android-Parsing-JSON-with-GSON
http://www.techrepublic.com/blog/software-engineer/use-gson-to-work-with-json-in-your-android-apps/
http://www.techrepublic.com/blog/software-engineer/use-gson-to-work-with-json-in-your-android-apps/
Hope this helps.
希望这可以帮助。
回答by Zaw Than oo
parse to JSONArray?
解析为JSONArray？
JSONArray jsonArray = (JSONArray)new JSONParser().parse(your json string);
For your code
对于您的代码
JSONObject jsonObject = (JSONObject)new JSONParser().parse(your json string);
JSONArray array = (JSONArray)jsonObject.get("recordset");
