ruby 将数组拆分为 m 大小的 n 组？
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Split array up into n-groups of m size?
提问by invaliduser
Possible Duplicate:
Need to split arrays to sub arrays of specified size in Ruby
可能的重复：
需要在 Ruby 中将数组拆分为指定大小的子数组
I'm looking to take an array---say [0,5,3,8,21,7,2] for example---and produce an array of arrays, split every so many places. If the above array were set to a, then
我正在寻找一个数组——例如 [0,5,3,8,21,7,2] 并生成一个数组数组，每隔这么多地方拆分。如果上面的数组被设置为a，那么
a.split_every(3)
would return [[0,5,3],[8,21,7][2]]
将返回 [[0,5,3],[8,21,7][2]]
Does this exist, or do I have to implement it myself?
这是否存在，还是我必须自己实现？
回答by Platinum Azure
a.each_slice(3).to_a
Or, to iterate (and not bother with keeping the array):
或者，迭代（而不是费心保留数组）：
a.each_slice(3) do |x,y,z|
p [x,y,z]
end
回答by maerics
a = (1..6).to_a
a.each_slice(2).to_a # => [[1, 2], [3, 4], [5, 6]]
a.each_slice(3).to_a # => [[1, 2, 3], [4, 5, 6]]
a.each_slice(4).to_a # => [[1, 2, 3, 4], [5, 6]]
