Ruby-on-rails Capybara 匹配器，用于显示按钮或链接
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Capybara matcher for presence of button or link
提问by mirelon
Users on web page don't distinguish between "button" and "link styled as button". Is there a way to add check whether a "button or link" is present on page?
网页上的用户不区分“按钮”和“链接样式为按钮”。有没有办法添加检查页面上是否存在“按钮或链接”？
For example Capybara has step:
例如水豚有步骤：
page.should have_button('Click me')
which does not find links styled as buttons.
它找不到样式为按钮的链接。
回答by mirelon
Updated answer (should matcher is deprecated in RSpec 3.0+):
更新的答案（如果匹配器在 RSpec 3.0+ 中被弃用）：
expect(page).to have_selector(:link_or_button, 'Click me')
Before:
前：
page.should have_selector(:link_or_button, 'Click me')
Followed from click_link_or_buttonwhich is defined here: https://github.com/jnicklas/capybara/blob/master/lib/capybara/node/actions.rb#L12
其次click_link_or_button是在此处定义：https: //github.com/jnicklas/capybara/blob/master/lib/capybara/node/actions.rb#L12
def click_link_or_button(locator)
find(:link_or_button, locator).click
end
alias_method :click_on, :click_link_or_button
It calls a selector :link_or_button. This selector is defined here: https://github.com/jnicklas/capybara/blob/master/lib/capybara/selector.rb#L143
它调用一个选择器:link_or_button。这个选择器在这里定义：https: //github.com/jnicklas/capybara/blob/master/lib/capybara/selector.rb#L143
Capybara.add_selector(:link_or_button) do
label "link or button"
xpath { |locator| XPath::HTML.link_or_button(locator) }
end
It calls this method: http://rdoc.info/github/jnicklas/xpath/XPath/HTML#link_or_button-instance_method
它调用这个方法：http: //rdoc.info/github/jnicklas/xpath/XPath/HTML#link_or_button-instance_method
# File 'lib/xpath/html.rb', line 33
def link_or_button(locator)
link(locator) + button(locator)
end
So i tried to check the presence of the selector and it worked:
所以我试图检查选择器的存在并且它起作用了：
page.should have_selector(:link_or_button, 'Click me')
回答by ardochhigh
Using the expectsyntax
使用期望语法
expect(page).to have_selector(:link_or_button, 'Click me')
This works without needing to define a custom matcher.
这无需定义自定义匹配器即可工作。
回答by Dave Oh
Personally I would give your button or link an id and look for that using
我个人会给你的按钮或链接一个 id 并使用
page.should have_css('#foo')
page.should have_css('#foo')
This way you can refer to the link or button without worrying about its implementation.
通过这种方式，您可以引用链接或按钮而无需担心其实现。
I always find this useful: https://gist.github.com/428105
我总是觉得这很有用：https: //gist.github.com/428105
回答by idrinkpabst
You can also use a custom matcher
您还可以使用自定义匹配器
RSpec::Matchers::define :have_link_or_button do |text|
match do |page|
Capybara.string(page.body).has_selector?(:link_or_button, text: text)
end
end
Then do
然后做
expect(page).to have_link_or_button('Login')
回答by Jon Kern
I had an odd case where some smoke tests marched across various customer-centric login pages that had slight variations on doing the login submit button... Driven by a Cucumber table of user, org, etc.
我有一个奇怪的例子，一些冒烟测试在各种以客户为中心的登录页面上进行，这些页面在登录提交按钮上有细微的变化......由用户、组织等的 Cucumber 表驱动。
# A bit of a hack, org_name is normally a subdomain, but sometimes it is the complete domain
def login(user, org_name)
# Use the below to automatically hit each user's org's server
if org_name.include? '.com'
Capybara.app_host = "http://#{org_name}"
else
Capybara.app_host = "http://#{org_name}.mydomain.com"
end
visit '/'
fill_in 'username', :with => user
fill_in 'userpwd', :with => '***'
begin
page.find(:link_or_button, 'submit')
click_on 'submit'
rescue Capybara::ElementNotFound
page.find(:link_or_button, 'Log In')
click_on 'Log In'
rescue Capybara::ElementNotFound
pending "Need to determine how to invoke the Login button for #{org_name} near Line ##{__LINE__} of #{__method__} in #{__FILE__} "
end
# -----------------------
# Work-around for modal popup saying SSL is mismatched if you are using actual production URLs
# The rescue is for cases that do not exhibit the modal pop-up
page.driver.browser.switch_to.alert.accept rescue Selenium::WebDriver::Error::NoAlertPresentError
# Ensure that login was successful
page.should_not have_content 'Login failed'
end
回答by simonmorley
I think you can use the find button instance method:
我认为您可以使用查找按钮实例方法：
(Capybara::Element) find_button(locator)
Using id, name, value.
使用 id、名称、值。
Or if you want a link
或者如果你想要一个链接
(Capybara::Element) find_link(locator)
来自：http: //rubydoc.info/github/jnicklas/capybara/master/Capybara/Node/Finders#find_button-instance_method
回答by Denis repon
if html:
如果是 html：
<a class="top-menu__item">text123
<span class="label">
<span class="label">86</span>
</span>
</a>
not work:
不行：
assert page.has_selector?(:link_or_button, text: 'text123')
assert page.should have_selector(:link_or_button, text: 'text123')
