C++ QVariant 到 QObject*

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时间:2020-08-28 13:58:48  来源:igfitidea点击:

QVariant to QObject*

c++qt4

提问by Leonardo M. Ramé

I'm trying to attach a pointer to an QListWidgetItem, to be used in the slot itemActivated.

我正在尝试将指针附加到QListWidgetItem,以在 slot 中使用itemActivated

The pointer I'm trying to attach is a QObject*descendant, so, my code is something like this:

我试图附加的指针是一个QObject*后代,所以,我的代码是这样的:

Image * im = new Image();  
// here I add data to my Image object
// now I create my item
QListWidgetItem * lst1 = new QListWidgetItem(*icon, serie->getSeriesInstanceUID(),  m_iconView);
// then I set my instance to a QVariant
QVariant v(QMetaType::QObjectStar, &im)
// now I "attach" the variant to the item.
lst1->setData(Qt::UserRole, v);
//After this, I connect the SIGNAL and SLOT
...

Now my problem, the itemActivatedslot. Here I need to extract my Image*from the variant, and I don't know how to.

现在我的问题,itemActivated插槽。在这里,我需要Image*从变体中提取我的,但我不知道该怎么做。

I tried this, but I get the error:

我试过这个,但我收到错误:

‘qt_metatype_id' is not a member of ‘QMetaTypeId'

“qt_metatype_id”不是“QMetaTypeId”的成员

void MainWindow::itemActivated( QListWidgetItem * item )
{
    Image * im = item->data(Qt::UserRole).value<Image *>();
    qDebug( im->getImage().toAscii() );
}

Any hint?

任何提示?

Image * im = item->data(Qt::UserRole).value<Image *>();

回答by Leonardo M. Ramé

The answer is this

答案是这个

// From QVariant to QObject *
QObject * obj = qvariant_cast<QObject *>(item->data(Qt::UserRole));
// from QObject* to myClass*
myClass * lmyClass = qobject_cast<myClass *>(obj);

回答by aschepler

That looks like an unusual use of QVariant. I'm not even sure if QVariantwould support holding a QObjector QObject*that way. Instead, I would try deriving from QListWidgetItemin order to add custom data, something like this:

这看起来像QVariant. 我什至不确定是否QVariant会支持持有QObjectQObject*那样。相反,我会尝试派生QListWidgetItem以添加自定义数据,如下所示:

class ImageListItem : public QListWidgetItem
{
  // (Not a Q_OBJECT)
public:
  ImageListItem(const QIcon & icon, const QString & text,
                Image * image,
                QListWidget * parent = 0, int type = Type);
  virtual ~ImageListItem();
  virtual QListWidgetItem* clone(); // virtual copy constructor
  Image * getImage() const;

private:
  Image * _image;
};

void MainWindow::itemActivated( QListWidgetItem * item )
{
     ImageListItem *image_item = dynamic_cast<ImageListItem*>(item);
     if ( !image_item )
     {
          qDebug("Not an image item");
     }
     else
     {
         Image * im = image_item->getImage();
         qDebug( im->getImage().toAscii() );
     }
}

Plus, the destructor of this new class gives you somewhere logical to make sure your Imagegets cleaned up.

另外,这个新类的析构函数为您提供了一个合乎逻辑的地方,以确保您Image得到清理。

回答by Kamil Klimek

You've inserted your Image class as QObject *, so get it out as QObject * also. Then perform qobject_cast and everything should be fine

您已将 Image 类作为 QObject * 插入,因此也将其作为 QObject * 取出。然后执行 qobject_cast 一切都应该没问题