PHP - 从一个整数生成一个 8 个字符的哈希
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PHP - Generate an 8 character hash from an integer
提问by doc
Is there a way to take any number, from say, 1 to 40000 and generate an 8 character hash?
有没有办法取任何数字，从 1 到 40000 并生成一个 8 个字符的哈希？
I was thinking of using base_convertbut couldn't figure out a way to force it to be an 8 character hash.
我正在考虑使用base_convert但无法想出一种方法将其强制为 8 个字符的哈希值。
Any help would be appreciated!
任何帮助，将不胜感激！
回答by Nathan Osman
Why don't you just run md5and take the first 8 characters?
你为什么不直接跑去md5取前 8 个字符呢？
Because you are wanting a hash, it doesn't matter whether portions are discarded, but rather that the same input will produce the same hash.
因为您想要一个散列，所以部分是否被丢弃并不重要，重要的是相同的输入将产生相同的散列。
$hash = substr(md5($num), 0, 8);
回答by Ignacio Vazquez-Abrams
>>> math.exp(math.log(40000)/8)
3.7606030930863934
Therefore you need 4 digit-symbols to produce a 8-character hash from 40000:
因此，您需要 4 个数字符号才能从 40000 生成 8 个字符的散列：
sprintf("%08s", base_convert($n, 10, 4))
回答by Ariel
For php:
对于 php：
$seed = 'JvKnrQWPsThuJteNQAuH';
$hash = sha1(uniqid($seed . mt_rand(), true));
# To get a shorter version of the hash, just use substr
$hash = substr($hash, 0, 10);
回答by symcbean
So you want to convert a 6 digit number into a 8 digit string reproducibly?
那么您想将 6 位数字可重复地转换为 8 位字符串吗？
sprintf("%08d", $number);
Certainly a hash is not reversible - but without a salt / IV it might be a bit easy to hack. A better solution might be:
当然，散列是不可逆的——但如果没有盐/IV，它可能有点容易被破解。更好的解决方案可能是：
substr(sha1($number . $some_secret),0,8);
C.
C。
回答by SteelBytes
there are many ways ...
有很多方法...
one example
一个例子
$x = ?
$s = '';
for ($i=0;$i<8;++$i)
{
$s .= chr( $x%26 + ord('a') );
$x /= 26;
}
回答by ghostdog74
$hash = substr(hash("sha256",$num), 0, 8);
