oracle 如何根据行本身的数量字段返回多个相同的行?

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时间:2020-09-18 21:28:43  来源:igfitidea点击:

How can I return multiple identical rows based on a quantity field in the row itself?

oracleselectrepeatrownum

提问by user126715

I'm using oracle to output line items in from a shopping app. Each item has a quantity field that may be greater than 1 and if it is, I'd like to return that row N times.

我正在使用 oracle 从购物应用程序中输出订单项。每个项目都有一个可能大于 1 的数量字段,如果是,我想返回该行 N 次。

Here's what I'm talking about for a table

这就是我在谈论一张桌子

product_id, quanity
1, 3,
2, 5

And I'm looking a query that would return

我正在寻找一个会返回的查询

1,3
1,3
1,3
2,5
2,5
2,5
2,5
2,5

Is this possible? I saw thisanswer for SQL Server 2005 and I'm looking for almost the exact thing in oracle. Building a dedicated numbers table is unfortunately not an option.

这可能吗?我在SQL Server 2005 中看到了这个答案,我正在寻找几乎与 oracle 完全相同的内容。不幸的是,构建专用的数字表不是一种选择。

回答by Gary Myers

I've used 15 as a maximum for the example, but you should set it to 9999 or whatever the maximum quantity you will support.

我在示例中使用了 15 作为最大值,但您应该将其设置为 9999 或任何您将支持的最大数量。

create table t (product_id number, quantity number);
insert into t values (1,3);
insert into t values (2,5);

select t.* 
  from t 
    join (select rownum rn from dual connect by level < 15) a 
                                 on a.rn <= t.quantity
order by 1;

回答by Martin Mares

First create sample data:

首先创建示例数据:

create table my_table (product_id number , quantity number);
insert into my_table(product_id, quantity) values(1,3);
insert into my_table(product_id, quantity) values(2,5);

And now run this SQL:

现在运行这个 SQL:

  SELECT product_id, quantity
    FROM my_table tproducts
        ,(    SELECT LEVEL AS lvl
                FROM dual
          CONNECT BY LEVEL <=  (SELECT MAX(quantity) FROM my_table)) tbl_sub
   WHERE tbl_sub.lvl BETWEEN 1 AND tproducts.quantity
ORDER BY product_id, lvl;

PRODUCT_ID   QUANTITY
---------- ----------
         1          3
         1          3
         1          3
         2          5
         2          5
         2          5
         2          5
         2          5

This question is propably same as this: how to calc ranges in oracle

这个问题可能与此相同:如何在 oracle 中计算范围

Update solution, for Oracle 9i:

更新解决方案,适用于 Oracle 9i

You can use pipelined_function() like this:

您可以像这样使用 pipelined_function():

CREATE TYPE SampleType AS OBJECT
(
  product_id number,
  quantity varchar2(2000)
)
/

CREATE TYPE SampleTypeSet AS TABLE OF SampleType
/

CREATE OR REPLACE FUNCTION GET_DATA RETURN SampleTypeSet
PIPELINED
IS
    l_one_row SampleType := SampleType(NULL, NULL);

BEGIN

    FOR cur_data IN (SELECT product_id, quantity FROM my_table ORDER BY product_id) LOOP
        FOR i IN 1..cur_data.quantity LOOP
            l_one_row.product_id := cur_data.product_id;
            l_one_row.quantity := cur_data.quantity;
            PIPE ROW(l_one_row);
        END LOOP;
    END LOOP;

    RETURN;
END GET_DATA;
/

Now you can do this:

现在你可以这样做:

SELECT * FROM TABLE(GET_DATA());

Or this:

或这个:

CREATE OR REPLACE VIEW VIEW_ALL_DATA AS SELECT * FROM TABLE(GET_DATA());
SELECT * FROM VIEW_ALL_DATA;

Both with same results.

两者结果相同。

(Based on my article pipelined function)

(基于我的文章流水线函数