Python 返回目录和子目录中的文件数
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Return number of files in directory and subdirectory
提问by Bob
Trying to create a function that returns the # of files found a directory and its subdirectories. Just need help getting started
尝试创建一个函数，该函数返回找到的目录及其子目录的文件数。只是需要帮助入门
回答by Blender
Just add an elifstatement that takes care of the directories:
只需添加一个elif处理目录的语句：
def fileCount(folder):
"count the number of files in a directory"
count = 0
for filename in os.listdir(folder):
path = os.path.join(folder, filename)
if os.path.isfile(path):
count += 1
elif os.path.isfolder(path):
count += fileCount(path)
return count
回答by Hans Then
Use os.walk. It will do the recursion for you. See http://www.pythonforbeginners.com/code-snippets-source-code/python-os-walk/for an example.
使用os.walk. 它会为你做递归。有关示例，请参见http://www.pythonforbeginners.com/code-snippets-source-code/python-os-walk/。
total = 0
for root, dirs, files in os.walk(folder):
total += len(files)
回答by kiriloff
One - liner
一字型
import os
cpt = sum([len(files) for r, d, files in os.walk("G:\CS\PYTHONPROJECTS")])
