javascript 你能让一个对象“可调用”吗？
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Can you make an object 'callable'?
提问by Septagram
Is it possible to make an object callable by implementing either callor applyon it, or in some other way? E.g.:
是否可以通过实现call或apply在对象上或以其他方式使对象可调用？例如：
var obj = {};
obj.call = function (context, arg1, arg2, ...) {
...
};
...
obj (a, b);
采纳答案by Max
No, but you can add properties onto a function, e.g.
不，但您可以向函数添加属性，例如
function foo(){}
foo.myProperty = "whatever";
EDIT: to "make" an object callable, you'll still have to do the above, but it might look something like:
编辑：要“制作”一个可调用的对象，您仍然必须执行上述操作，但它可能看起来像：
// Augments func with object's properties
function makeCallable(object, func){
for(var prop in object){
if(object.hasOwnProperty(prop)){
func[prop] = object[prop];
}
}
}
And then you'd just use the "func" function instead of the object. Really all this method does is copy properties between two objects, but...it might help you.
然后你只需使用“func”函数而不是对象。实际上，此方法所做的只是在两个对象之间复制属性，但是……它可能对您有所帮助。
回答by 0xc0de
ES6has better solution for this now. If you create your objects in a different way (using class, extending 'Function' type), you can have a callable instance of it.
ES6现在有更好的解决方案。如果您以不同的方式创建您的对象（使用class, extending 'Function' 类型），您可以拥有它的一个可调用实例。
See also: How to extend Function with ES6 classes?
另请参阅：如何使用 ES6 类扩展函数？
回答by Rodrigo Rodrigues
Following the same line of @Max, but using ES6 extensions to Objectto pass all properties and prototype of an object objto the callable func.
遵循@Max 的同一行，但使用 ES6 扩展将Object对象的所有属性和原型传递obj给 callable func。
Object.assign(func, obj);
Object.setPrototypeOf(func, Object.getPrototypeOf(obj));
回答by Brasten Sager
Others have provided the current answer ("no") and some workarounds. As far as first-class support in the future, I suggested this very thing to the es-discuss mailing list. The idea did not get very far that time around, but perhaps some additional interest would help get the idea moving again.
其他人提供了当前的答案（“否”）和一些解决方法。就未来的一流支持而言，我向 es-discuss 邮件列表建议了这一点。那个时候这个想法并没有走得太远，但也许一些额外的兴趣会帮助这个想法再次动起来。
