Laravel 将 JSON 转换为数组?
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Laravel casting JSON to array?
提问by jycr753
I'm trying to convert the a JSON field to array. For example the model is like this:
我正在尝试将 JSON 字段转换为数组。例如模型是这样的:
protected $casts = [
'content' => 'array'
];
While in insert the content inside, I do it like this:
在插入内容时,我是这样做的:
'content'=> json_encode([
'description' => $faker->paragraph(3),
'about' => $faker->paragraph(2),
'info' => $faker->paragraph(2),
'updated' => $faker->dateTimeBetween('-1 years', 'now')
]),
But while getting the data it prints a string, nothing else.
但是在获取数据时它会打印一个字符串,没有别的。
The migration in this part looks like this:
这部分的迁移如下所示:
$campaign->json('content');
Sample of the output:
输出示例:
"content": "{\"description\":\"Ut quas quo odio illo. Voluptates quia fuga itaque sint. Velit sapiente fugit ea ut ducimus sint tempora eligendi. Ea et molestiae consequuntur quibusdam soluta voluptatem.\",\"about\":\"Aut voluptates et iste ut perspiciatis. Esse sunt ullam inventore sit doloremque et quisquam.\",\"info\":\"Corrupti et facere exercitationem consequatur aspernatur quo saepe. Omnis et tempore enim ut. Quia magnam quia enim et eos enim.\",\"updated\":{\"date\":\"2015-11-22 08:25:13.000000\",\"timezone_type\":3,\"timezone\":\"UTC\"}}",
Any ideas why?
任何想法为什么?
回答by Marcin Nabia?ek
When you define array
cast you don't need to do any json_encode
or json_decode
. When you want to insert, simple you need to do:
当您定义array
演员表时,您无需执行任何json_encode
或json_decode
. 当你想插入时,你需要做的很简单:
'content'=> [
'description' => $faker->paragraph(3),
'about' => $faker->paragraph(2),
'info' => $faker->paragraph(2),
'updated' => $faker->dateTimeBetween('-1 years', 'now')
],
Laravel will do the rest
Laravel 将完成剩下的工作
And when you want to get content
field data, you simple need to use:
当您想获取content
字段数据时,您只需使用:
$campaign->content;
and you will have here array, so if you want to display description, you simple need to do:
并且您将在此处拥有数组,因此如果您想显示描述,您只需执行以下操作:
echo $campaign->content['description'];
回答by zt1983811
Just use json_decode
with option array true
只需使用json_decode
与option array true
json_decode($casts['content'], true));
回答by mangonights
If you want your mind blown...
如果你想让你的头脑爆炸......
// automatically handles json_encode, json_decode to php object
protected $casts = [
'db_json_column' => 'object'
];
$model->db_json_column = $array; // persisted as json
$object = $model->db_json_column; // retrieved as object
or,
或者,
// automatically handles json_encode, json_decode to php array
protected $casts = [
'db_json_column' => 'array'
];
$model->db_json_column = $array; // persisted as json
$array = $model->db_json_column; // retrieved as array