scala 如何将句子拆分为多个空格分隔的单词？
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How to split sentence into words separated by multiple spaces?
提问by yalkris
The following code:
以下代码：
val sentence = "1 2 3 4".split(" ")
gives me:
给我：
Array(1, 2, "", 3, "", "", 4)
but I'd rather want to have only the words:
但我宁愿只拥有这些词：
Array(1, 2, 3, 4)
How can I split the sentence when the words are separated by multiple spaces?
当单词被多个空格分隔时，如何拆分句子？
回答by Tim
Use a regular expression:
使用正则表达式：
scala> "1 2 3".split(" +")
res1: Array[String] = Array(1, 2, 3)
The "+" means "one or more of the previous" (previous being a space).
“+”表示“前一个或多个”（前一个是空格）。
Better yet, if you want to split on all whitespace:
更好的是，如果您想拆分所有空白：
scala> "1 2 3".split("\s+")
res2: Array[String] = Array(1, 2, 3)
(Where "\\s"is a Patternwhich matches any whitespace. Look herefor more examples.)
回答by Brian
You can filter out the ""from the split Array.
您可以""从 split 中过滤掉Array。
scala> val sentence = "1 2 3 4".split(" ").filterNot(_ == "")
sentence: Array[java.lang.String] = Array(1, 2, 3, 4)
回答by elm
This regular expression \\W+delivers (alphaunmerical) words, thus
此正则表达式\\W+提供（字母数字）单词，因此
val sentence = "1 2 3 4".split("\W+")
sentence: Array[String] = Array(1, 2, 3, 4)
For ease of use, in Scala 2.10.* and 2.11.* consider
为了便于使用，在 Scala 2.10.* 和 2.11.* 中考虑
implicit class RichString(val s: String) extends AnyVal {
def words = s.split("\W+")
}
Thus,
因此，
sentence.words
res: Array[String] = Array(1, 2, 3, 4)
