可执行文件的 Java 文件路径中的空格
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/16639285/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Spaces in Java file path to an executable
提问by user2399735
Ok, I know this is probably a noobish question, but I'm pretty new to Java, and it'll probably be fairly easy to answer. What I'm trying to do is make a program that will use a file path to open Firefox, but it seems there is a problem with the file path. I did some research and used the double slash to nullify the escape characters, but it still doesn't work. I think it has to do with the fact that there spaces in some of the directories' names. Here is my code:
好的，我知道这可能是一个菜鸟问题，但我对 Java 还很陌生，而且可能很容易回答。我想要做的是制作一个程序，该程序将使用文件路径打开 Firefox，但文件路径似乎有问题。我做了一些研究并使用双斜杠来取消转义字符，但它仍然不起作用。我认为这与某些目录名称中有空格有关。这是我的代码：
import java.io.IOException;
public class Automation {
public static void main(String[] args) throws IOException {
Process p = Runtime.getRuntime().exec("C:\Program Files (x86)\Mozilla Firefox\firefox.exe");
}
}
I know its pretty simple, but I can't still figure it out. Any help is appreciated.
我知道它很简单，但我仍然无法弄清楚。任何帮助表示赞赏。
回答by Mena
Process p = Runtime.getRuntime().exec("\"C:\Program Files (x86)\Mozilla firefox\firefox.exe\"");
... or with Java 7 against Windows ...
... 或者使用 Java 7 来对抗 Windows ...
String[] command = new String[] {
"C:" +
File.separator +
"Program Files (x86)" +
File.separator +
"Mozilla firefox" +
File.separator +
"firefox.exe"
};
Process p = Runtime.getRuntime().exec(command);
回答by Laksitha Ranasingha
The ideal solution for your problem should be like this.
您的问题的理想解决方案应该是这样的。
String [] cmds = new String [1];
cmds[0] = "C:\Program Files (x86)\Mozilla firefox\firefox.exe";
Process p = Runtime.getRuntime().exec(cmds);
This is because Runtime.getRuntime().exec()actually doesn't execute the program as command line interpreter does. So you need to use a parameter array when you have white spaces in the path. you can provide extra flags/options in this array (ex: open).
这是因为Runtime.getRuntime().exec()实际上不像命令行解释器那样执行程序。因此，当路径中有空格时，您需要使用参数数组。您可以在此数组中提供额外的标志/选项（例如：打开）。
This is some extra information. As far as I know Windows is perfectly happy with forward slashes (/), because Windows API accepts forward and backward slashes (starting from MS DOS 2.0i think). for example you can do dir "c:/Program Files (x86)"will work fine give you the directory list. Furthermore, without white spaces Process p = Runtime.getRuntime().exec("C:/SomeProgram/someprogram.exe");works fine . However the recommended way is to get the file separator from the environment. That's using File.separator
这是一些额外的信息。据我所知，Windows 对正斜杠 ( /)非常满意，因为 Windows API 接受正斜杠和反斜杠（从MS DOS 2.0我认为开始）。例如，你可以dir "c:/Program Files (x86)"给你目录列表。此外，没有空格也能Process p = Runtime.getRuntime().exec("C:/SomeProgram/someprogram.exe");正常工作。但是，推荐的方法是从环境中获取文件分隔符。那是用File.separator
回答by xtraclass
"\"C:\ .......\""
So you can "escape" the blanks.
所以你可以“逃避”空白。
