javascript PHP 相当于 indexOf
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PHP equivalent of indexOf
提问by Cameron
I have the following JS:
我有以下JS：
if(window.location.href.indexOf("search.php") != -1
|| window.location.href.indexOf("list.php") != -1
|| window.location.href.indexOf("view.php") != -1
|| window.location.href.indexOf("contact.php") != -1) {
But want to convert it to PHP. What is the equivalent of indexOf in PHP or the best way to do this in PHP.
但是想把它转换成PHP。什么是 PHP 中 indexOf 的等价物或在 PHP 中执行此操作的最佳方法。
I don't understand the strpos examples people are linking to below. Perhaps an example more in line with what I have done in JS?
我不明白人们在下面链接的 strpos 示例。也许一个更符合我在 JS 中所做的例子？
回答by de Raad
The question asks for an equivalent. PHP's strpos() does not work on an array, whereas javascript's indexOf does (by treating a string as an array automatically). So here's a PHP equivalent
该问题要求等效。PHP 的 strpos() 不适用于数组，而 javascript 的 indexOf 可以（通过自动将字符串视为数组）。所以这是一个 PHP 等价物
function indexOf($array, $word) {
foreach($array as $key => $value) if($value === $word) return $key;
return -1;
}
// Example: indexOf(['hi','bye'], 'bye') returns 1
回答by nickb
strpos()should do the trick, also it returns boolean falseon failure.
strpos()应该可以解决问题，它也会false在失败时返回布尔值。
JS version:
JS版本：
The indexOf() method returns the position of the first occurrence of a specified value in a string. This method returns -1 if the value to search for never occurs. Note: The indexOf() method is case sensitive.
indexOf() 方法返回指定值在字符串中第一次出现的位置。如果从未出现要搜索的值，则此方法返回 -1。注意： indexOf() 方法区分大小写。
PHP version:
PHP版本：
int strpos ( string $haystack , mixed $needle [, int $offset = 0 ] )
Find the numeric position of the first occurrence of needle in the haystack string. Returns the position of where the needle exists relative to the beginning of the haystack string (independent of offset). Also note that string positions start at 0, and not 1. Returns FALSE if the needle was not found.
在 haystack 字符串中找到第一个出现的针的数字位置。返回针相对于 haystack 字符串开头的位置（与偏移量无关）。另请注意，字符串位置从 0 开始，而不是 1。如果未找到针，则返回 FALSE。
回答by Rawkode
Although your JavaScript code is using indexOf(), PHP actually has a better way of handling what you want to achieve.
尽管您的 JavaScript 代码使用的是indexOf()，但 PHP 实际上有更好的方式来处理您想要实现的目标。
You simply have to check the script name in your URL, then perform an action(s) based on it.
您只需检查 URL 中的脚本名称，然后根据它执行操作。
In my opinion, PHP switchstatement is better than ifstatements in combination with PHP strpos()function.
在我看来，PHPswitch语句比if语句结合 PHPstrpos()函数要好。
Below is an illustration of how you can achieve that using a PHP switch statement:
下面是如何使用 PHP switch 语句实现这一目标的说明：
switch(basename($_SERVER['SCRIPT_NAME'])) {
case 'search.php':
// Script to run for search.php
break;
case 'list.php':
// Script to run for list.php
break;
case 'view.php':
// Script to run for view.php
break;
case 'contact.php':
break;
default:
// Perform code on anything except the above cases.
break;
}
回答by Brett Zamir
In reply to your secondary question, strpos could be used as follows:
在回答您的次要问题时，可以按如下方式使用 strpos：
if (strpos($_SERVER['SCRIPT_NAME'], "search.php") !== false
|| strpos($_SERVER['SCRIPT_NAME'], "list.php") !== false
|| strpos($_SERVER['SCRIPT_NAME'], "view.php") !== false
|| strpos($_SERVER['SCRIPT_NAME'], "contact.php") !== false) {
...though indeed Rawkode's answer is more elegant.
...虽然确实 Rawkode 的回答更优雅。
