bash 从文件中读取字符串并转换为 int
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Read string from file and convert into an int
提问by Ghost
I have a txt file with ONLY a number inside; it can be any number, how can i read it from bash and convert it into an int?
我有一个 txt 文件，里面只有一个数字；它可以是任何数字，我如何从 bash 读取它并将其转换为 int？
As i said, the only thing in the file is the number, no other thing, but when reading it, bash gets it as a string.
正如我所说，文件中唯一的东西是数字，没有其他东西，但是在读取它时，bash 将其作为字符串获取。
Thanks in advance!
提前致谢！
回答by Barmar
Use declareor typeset:
使用declare或typeset：
typeset -i variable=$(cat filename)
