JSON.stringify 一个带有 Knockout JS 变量的对象
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JSON.stringify an object with Knockout JS variables
提问by Chris Dixon
Current scenario:
当前场景：
function Employee(data) {
var self = this;
// variables
this.Forename = ko.observable(data.Forename);
this.Surname = ko.observable(data.Surname);
this.Save = function () {
var obj = JSON.stringify(self); // Without ko.observables, this works fine. self() doesn't work obviously.
console.log(obj);
};
}
I think what I'm trying to do is pretty straight forward, get all the observable values without going through every single one of them, and creating a JSON string using the stringify function. This is easy to do without observables, is there a simple way to do it with them?
我认为我想要做的很简单，获取所有可观察值，而无需遍历其中的每一个，并使用 stringify 函数创建一个 JSON 字符串。没有 observables 这很容易做到，有没有一种简单的方法可以用它们来做？
回答by Richard Dalton
Knockout has a built in toJSONfunction to do exactly this:
Knockout 有一个内置的toJSON函数来做到这一点：
var json = ko.toJSON(viewModel);
ko.toJSON— this produces a JSON string representing your view model's data. Internally, it simply calls ko.toJS on your view model, and then uses the browser's native JSON serializer on the result. Note: for this to work on older browsers that have no native JSON serializer (e.g., IE 7 or earlier), you must also reference the json2.js library.
ko.toJSON— 这会生成一个 JSON 字符串，表示您的视图模型的数据。在内部，它只是在您的视图模型上调用 ko.toJS，然后在结果上使用浏览器的本机 JSON 序列化程序。注意：为了在没有原生 JSON 序列化程序的旧浏览器（例如，IE 7 或更早版本）上工作，您还必须引用 json2.js 库。
回答by ebram khalil
You can do this by 2 ways :
你可以通过两种方式做到这一点：
first:
第一的：
var json = ko.toJSON(ko.mapping.toJS(viewModel))
Second
第二
var json = JSON.stringify(ko.mapping.toJS(viewModel))
回答by Paul Manzotti
Have you looked at the knockout mapping plugin?
你看过淘汰赛地图插件吗？
var unmapped = ko.mapping.toJS(viewModel);
