如何更新 PHP 关联数组中特定键的值？
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How to update specific key's value in an associative array in PHP?
提问by PHPLover
I've a following associative array named $data
我有一个名为的以下关联数组 $data
Array
(
[0] => Array
(
[transaction_user_id] => 359691e27b23f8ef3f8e1c50315cd506
[transaction_no] => 19500912050218
[transaction_total_amount] => 589.00
[transaction_date] => 1335932419
[transaction_status] => cancelled
)
[1] => Array
(
[transaction_user_id] => 9def02e6337b888d6dbe5617a172c18d
[transaction_no] => 36010512050819
[transaction_total_amount] => 79.00
[transaction_date] => 1336476696
[transaction_status] => cancelled
)
[2] => Array
(
[transaction_user_id] => 9def02e6337b888d6dbe5617a172c18d
[transaction_no] => 19020512050820
[transaction_total_amount] => 299.00
[transaction_date] => 1336476739
[transaction_status] => cancelled
)
[3] => Array
(
[transaction_user_id] => 9def02e6337b888d6dbe5617a172c18d
[transaction_no] => 27050512050821
[transaction_total_amount] => 79.00
[transaction_date] => 1336476927
[transaction_status] => cancelled
)
[4] => Array
(
[transaction_user_id] => 8e9050a3646c98342b9ba079fba80982
[transaction_no] => 12070512050822
[transaction_total_amount] => 129.00
[transaction_date] => 1336477032
[transaction_status] => cancelled
)
)
and I want to convert the value of key [transaction_date]into user readable format (i.e. mm/dd/yyyy). For that I written the following code in a function which returns the whole array:
我想将键的值转换[transaction_date]为用户可读的格式（即 mm/dd/yyyy）。为此，我在返回整个数组的函数中编写了以下代码：
foreach($data as $value)
{
$value[transaction_date]=date('d/m/Y',$value[transaction_date]);
}
return $data;
My problem is I'm getting the same array without changing the value of [transaction_date]for all the array elements. Actually array with updated values for [transaction_date]is expected to be returned.
Can anyone help me out to resolve this issue? Thanks in advance.
我的问题是我得到了相同的数组而不改变[transaction_date]所有数组元素的值。实际上，[transaction_date]预计将返回具有更新值的数组。谁能帮我解决这个问题？提前致谢。
回答by Rikesh
Change your foreach to something like this, You are not assigning data back to your return variable $dataafter performing operation on that.
将您的 foreach 更改为这样的内容，$data在对其执行操作后，您不会将数据分配回您的返回变量。
foreach($data as $key => $value)
{
$data[$key]['transaction_date'] = date('d/m/Y',$value['transaction_date']);
}
回答by Thank you
This will work too!
这也行！
foreach($data as &$value) {
$value['transaction_date'] = date('d/m/Y', $value['transaction_date']);
}
Yay for alternatives!
是的替代品！
回答by SJ00
PHP array_walk()function is specifically for altering array.
PHP array_walk()函数专门用于更改数组。
Try this:
尝试这个：
array_walk ( $data, function (&$key) {
$key["transaction_date"] = date('d/m/Y',$key["transaction_date"]);
});
回答by Naveenkumar N
Use array_walk_recursive function for multi-denominational array.
对多面额数组使用 array_walk_recursive 函数。
array_walk_recursive($data, function (&$v, $k) {
if($k == 'transaction_date'){
$v = date('d/m/Y',$v);
}
});
回答by Ivan Fretes
This a single solution, in where your_fieldis a field that will set and new_valueis a new value field, that can a function or a single value
这是一个单一的解决方案，其中your_field是一个将设置的字段，而new_value是一个新值字段，它可以是一个函数或单个值
foreach ($array as $key => $item) {
$item["your_field"] = "new_value";
$array[$key] = $item;
}
In your case new_valuewill be a date() function
在你的情况下new_value将是一个 date() 函数
回答by CoBolt
foreach($data as $value)
{
$value["transaction_date"] = date('d/m/Y',$value["transaction_date"]);
}
return $data;
