C++ 如何删除 VS 警告 C4091: 'typedef ' : 当没有声明变量时，在 'SPREADSHEET' 的左侧被忽略
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How can I remove the VS warning C4091: 'typedef ' : ignored on left of 'SPREADSHEET' when no variable is declared
提问by Wartin
This warning is triggered multiple times in my code by the same declaration, which reads :
此警告在我的代码中由同一个声明多次触发，内容如下：
// Spreadsheet structure
typedef struct SPREADSHEET
{
int ID; // ID of the spreadsheet
UINT nLines; // Number of lines
void CopyFrom(const SPREADSHEET* src)
{
ID = src->ID;
nLines = src->nLines;
}
};
I don't want to just turn off that warning,
我不想只是关闭那个警告，
but rather change the code so that the warning doesn't come up !
而是更改代码，以免出现警告！
NOTE : I don't want to declare any variables here (it's a header file), only define what the struct 'SPREADSHEET' should include...
注意：我不想在这里声明任何变量（它是一个头文件），只定义结构“SPREADSHEET”应该包含的内容......
回答by Blindy
Delete typedef. It's the C way of declaring structs, C++ does it automatically for you.
删除typedef。这是声明结构的 C 方式，C++ 会自动为您完成。
回答by MSN
You need to add some identifier before the terminating ;, e.g.:
您需要在终止之前添加一些标识符;，例如：
typedef struct BLAH { ... } BLAH;
回答by sth
Just remove "typedef". You declare a new struct and the typedefkeyword isn't used for that. You would use typedefto define a new name for an existing type, like this:
只需删除“ typedef”。您声明了一个新的结构，而typedef关键字不用于该目的。您将使用typedef为现有类型定义新名称，如下所示：
typedef int number;
回答by Srikant
Yes, the BLAHafterthe closing brace is important to make the typedefa valid one. You can remove the SPREADSHEETfrom the present place and keep it in between the }and the ;.
是的，右大括号BLAH之后的对于使之typedef有效很重要。您可以SPREADSHEET从当前位置删除 ，并将其保留在}和之间;。
回答by Neoheurist
My interpretation of this warning is that the compiler is indicating that the typedefkeyword is unnecessary because a variable is not being declared. and therefore if the intention of the code is to simply declare a structthe typedefis superfluous.
我对这个警告的解释是编译器指示typedef关键字是不必要的，因为没有声明变量。因此，如果代码的意图是简单地声明struct了typedef是多余的。
