php 从 URL 获取 JSON 对象
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Get JSON object from URL
提问by user2199343
I have a URL that returns a JSON object like this:
我有一个返回 JSON 对象的 URL，如下所示：
{
"expires_in":5180976,
"access_token":"AQXzQgKTpTSjs-qiBh30aMgm3_Kb53oIf-VA733BpAogVE5jpz3jujU65WJ1XXSvVm1xr2LslGLLCWTNV5Kd_8J1YUx26axkt1E-vsOdvUAgMFH1VJwtclAXdaxRxk5UtmCWeISB6rx6NtvDt7yohnaarpBJjHWMsWYtpNn6nD87n0syud0"
}
I want to get the access_tokenvalue. So how can I retrieve it through PHP?
我想获得access_token价值。那么如何通过PHP检索它呢？
回答by Prisoner
$json = file_get_contents('url_here');
$obj = json_decode($json);
echo $obj->access_token;
For this to work, file_get_contentsrequires that allow_url_fopenis enabled. This can be done at runtime by including:
为此，file_get_contents需要allow_url_fopen启用它。这可以在运行时完成，包括：
ini_set("allow_url_fopen", 1);
You can also use curlto get the url. To use curl, you can use the example found here:
您也可以使用curl来获取 url。要使用 curl，您可以使用此处找到的示例：
$ch = curl_init();
// IMPORTANT: the below line is a security risk, read https://paragonie.com/blog/2017/10/certainty-automated-cacert-pem-management-for-php-software
// in most cases, you should set it to true
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'url_here');
$result = curl_exec($ch);
curl_close($ch);
$obj = json_decode($result);
echo $obj->access_token;
回答by gaRex
$url = 'http://.../.../yoururl/...';
$obj = json_decode(file_get_contents($url), true);
echo $obj['access_token'];
Php also can use properties with dashes:
PHP 还可以使用带破折号的属性：
garex@ustimenko ~/src/ekapusta/deploy $ psysh
Psy Shell v0.4.4 (PHP 5.5.3-1ubuntu2.6 — cli) by Justin Hileman
>>> $q = new stdClass;
=> <stdClass #000000005f2b81c80000000076756fef> {}
>>> $q->{'qwert-y'} = 123
=> 123
>>> var_dump($q);
class stdClass#174 (1) {
public $qwert-y =>
int(123)
}
=> null
回答by netblognet
You could use PHP's json_decodefunction:
你可以使用 PHP 的json_decode函数：
$url = "http://urlToYourJsonFile.com";
$json = file_get_contents($url);
$json_data = json_decode($json, true);
echo "My token: ". $json_data["access_token"];
回答by Toqeer Ahmed
// Get the string from the URL
$json = file_get_contents('https://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452');
// Decode the JSON string into an object
$obj = json_decode($json);
// In the case of this input, do key and array lookups to get the values
var_dump($obj->results[0]->formatted_address);
回答by Nick
You need to read about json_decode function http://php.net/manual/en/function.json-decode.php
您需要阅读有关 json_decode 函数http://php.net/manual/en/function.json-decode.php
Here you go
干得好
$json = '{"expires_in":5180976,"access_token":"AQXzQgKTpTSjs-qiBh30aMgm3_Kb53oIf-VA733BpAogVE5jpz3jujU65WJ1XXSvVm1xr2LslGLLCWTNV5Kd_8J1YUx26axkt1E-vsOdvUAgMFH1VJwtclAXdaxRxk5UtmCWeISB6rx6NtvDt7yohnaarpBJjHWMsWYtpNn6nD87n0syud0"}';
//OR $json = file_get_contents('http://someurl.dev/...');
$obj = json_decode($json);
var_dump($obj-> access_token);
//OR
$arr = json_decode($json, true);
var_dump($arr['access_token']);
回答by Ya-Ze Lin
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'url_here');
$result = curl_exec($ch);
curl_close($ch);
$obj = json_decode($result);
echo $obj->access_token;
回答by Firdous bhat
file_get_contents()is not fetching the data from url,then i tried curland it's working fine.
file_get_contents()没有从 url 获取数据，然后我试过了curl，它工作正常。
回答by Billy Mainor Lemus
my solution only works for the next cases: if you are mistaking a multidimensaional array into a single one
我的解决方案仅适用于以下情况：如果您将多维数组误认为一个数组
$json = file_get_contents('url_json'); //get the json
$objhigher=json_decode($json); //converts to an object
$objlower = $objhigher[0]; // if the json response its multidimensional this lowers it
echo "<pre>"; //box for code
print_r($objlower); //prints the object with all key and values
echo $objlower->access_token; //prints the variable
i know that the answer was has already been answered but for those who came here looking for something i hope this can help you
我知道答案已经得到了回答，但对于那些来这里寻找东西的人，我希望这可以帮助你
回答by YB Idea
$curl_handle=curl_init();
curl_setopt($curl_handle, CURLOPT_URL,'https://www.xxxSite/get_quote/ajaxGetQuoteJSON.jsp?symbol=IRCTC&series=EQ');
//Set the GET method by giving 0 value and for POST set as 1
//curl_setopt($curl_handle, CURLOPT_POST, 0);
curl_setopt($curl_handle, CURLOPT_CUSTOMREQUEST, "GET");
curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2);
curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1);
$query = curl_exec($curl_handle);
$data = json_decode($query, true);
curl_close($curl_handle);
//print complete object, just echo the variable not work so you need to use print_r to show the result
echo print_r( $data);
//at first layer
echo $data["tradedDate"];
//Inside the second layer
echo $data["data"][0]["companyName"];
Some time you might get 405, set the method type correctly.
有时您可能会收到 405，请正确设置方法类型。
回答by jamal arradi
When you are using curlsometimes give you 403 (access forbidden)
Solved by adding this line to emulate browser.
当您使用时curl有时会给您 403 (access forbidden) 通过添加此行来模拟浏览器来解决。
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 1.0.3705; .NET CLR 1.1.4322)');
Hope this help someone.
希望这有助于某人。
