Laravel 5.4：使用参数从控制器调用路由函数
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Laravel 5.4: call a route function from controller with parameters
提问by Ajmal Razeel
I want to call a route function from my controller with some parameters.
我想用一些参数从我的控制器调用路由函数。
This is my Controller
这是我的控制器
public function myFunction($id, $name)
{
$id = 1;
$name = 'john';
return redirect()->route('details/' . $id . '/' . $name);
}
This is my route
这是我的路线
Route::get('details/{id}/{name}',['uses' =>'My_controller@myFunction']);
This is the error I get when I run the script.
这是我运行脚本时得到的错误。
InvalidArgumentException in UrlGenerator.php line 304:
Route [details/1/john] not defined.
Please Help
请帮忙
回答by verax
route()helper requires you to pass route name and parameters:
route()helper 要求您传递路由名称和参数：
function route($name, $parameters = [], $absolute = true)
{
return app('url')->route($name, $parameters, $absolute);
}
So you need to give your route a name:
所以你需要给你的路线一个名字：
Route::get('details/{id}/{name}',['uses' =>'My_controller@myFunction'])->name('details');
..and then you can pass parameters in an array:
..然后你可以在数组中传递参数：
return redirect()->route('details', array('id' => $id, 'name' => $name));
Hope this helps
希望这可以帮助
